Answer:
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Explanation:
If this doesn't help, leave a comment and I'll try to help more!
Answer:
The root is:
Explanation:
Use this script in Matlab:
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function [c, err, yc] = bisect (f, a, b, delta)
% f the function introduce as n anonymous function
% - a y b are the initial and the final value respectively
% - delta is the tolerance or error.
% - c is the root
% - yc = f(c)
% - err is the stimated error for c
ya = feval(f, a);
yb = feval(f, b);
if ya*yb > 0, return, end
max1 = 1 + round((log(b-a) - log(delta)) / log(2));
for k = 1:max1
c = (a + b) / 2;
yc = feval(f, c);
if yc == 0
a = c;
b = c;
elseif yb*yc > 0
b = c;
yb = yc;
else
a = c;
ya = yc;
end
if b-a < delta, break, end
end
c = (a + b) / 2;
err = abs(b - a);
yc = feval(f, c);
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Enter the function in matlab like this:
f= @(x) 0.005*(exp(2*x)*cos(x))
You should get this result:
f =
function_handle with value:
@(x)0.005*(exp(2*x)*cos(x))
Now run the code like this:
[c, err, yc] = bisect (f, 1, 2, 1e-10)
You should get this result:
c =
1.5708
err =
5.8208e-11
yc =
-3.0708e-12
In addition, you can use the plot function to verify your results:
fplot(f,[1,2])
grid on
Answer:
a) 1011
Explanation:
In 4 bit two's complement representation, the first bit is the sign bit.
If the sign bit is 1, the number is negative.
If the sign bit is 0, the number is positive.
What is the magnitude of the sign bit?
In n-bit two's complement representation, the magnitude of the sign bit is:
So, in 4-bit two's complement representation, the magnitude of the sign bit is:
Since the number is negative, the value of this bit is -8.
The other bits are magnitude bits, positive.
We have that the sum of these bits must be -5, and we already have -8. So what should be the value of these last 3 bits?
First, i am going to solve this equation to find the decimal value of the last three bits.
So, the last three bits are:
The binary encoding of the number -5 is:
a) 1011