Question

If t(x)=-x+3, then what is f(x)=(t*t)(x)

Answer 1

Answer:

$f(x) = {x}^{2} - 6x + 9$

Step-by-step explanation:

If f(x) = (tt)(x), that's essentially squaring t(x) so

$f(x) = {t(x)}^2 \\ f(x) = (-x +3)^2 \\ f(x) = (-x +3)(-x +3) \\ f(x) = -x(-x +3) +3(-x +3)\\ f(x) = x^2 -3x -3x +9 \\ f(x) = x^2 -6x +9$