Question

A rock is dropped off a 500-foot cliff. After 1 second the rock is traveling 32 feet per second then after 4 seconds the rock starts travelling 128 feet per second.
Part A- Assume the relationship between time, t, and speed, s, is linear and write an equation describing the relationship. Use ordered pairs of the form (speed, time)
Part B- Use the equation to determine the speed of the rock 5 seconds after is dropped.

Answer 1

Answer:

A. The equation describing the relationship between speed and time is:

s = 32t

Ordered pairs of the form (speed, time) are:

(32, 1)

(64, 2)

(96, 3)

(128, 4)

B.

Using s = 32t, we have:

s = 32 * 5 = 160 feet per second

Step-by-step explanation:

1. Let's review the information provided to us to answer the question correctly:

Height of the cliff = 500 feet

Speed after one second = 32 feet per second

Speed after four seconds = 128 feet per second

2. Assume the relationship between time, t, and speed, s, is linear and write an equation describing the relationship. Use ordered pairs of the form (speed, time)

The equation describing the relationship between speed and time is:

s = 32t

Ordered pairs of the form (speed, time) are:

(32, 1)

(64, 2)

(96, 3)

(128, 4)

3.  Use the equation to determine the speed of the rock 5 seconds after is dropped.

s = 32t

s = 32 * 5 = 160 feet per second

Note: Same answer to question 14436233, answered by me today.