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pashok25 [27]
3 years ago
10

A rock is dropped off a 500-foot cliff. After 1 second the rock is traveling 32 feet per second then after 4 seconds the rock st

arts travelling 128 feet per second.
Part A- Assume the relationship between time, t, and speed, s, is linear and write an equation describing the relationship. Use ordered pairs of the form (speed, time)
Part B- Use the equation to determine the speed of the rock 5 seconds after is dropped.
Mathematics
1 answer:
kozerog [31]3 years ago
4 0

Answer:

<u>A. The equation describing the relationship between speed and time is:</u>

<u>s = 32t</u>

<u>Ordered pairs of the form (speed, time) are:</u>

<u>(32, 1)</u>

<u>(64, 2)</u>

<u>(96, 3)</u>

<u>(128, 4)</u>

<u>B. </u>

<u>Using s = 32t, we have:</u>

<u>s = 32 * 5 = 160 feet per second</u>

Step-by-step explanation:

1. Let's review the information provided to us to answer the question correctly:

Height of the cliff = 500 feet

Speed after one second = 32 feet per second

Speed after four seconds = 128 feet per second

2. Assume the relationship between time, t, and speed, s, is linear and write an equation describing the relationship. Use ordered pairs of the form (speed, time)

The equation describing the relationship between speed and time is:

s = 32t

Ordered pairs of the form (speed, time) are:

(32, 1)

(64, 2)

(96, 3)

(128, 4)

3.  Use the equation to determine the speed of the rock 5 seconds after is dropped.

s = 32t

s = 32 * 5 = 160 feet per second

Note: Same answer to question 14436233, answered by me today.

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Step-by-step explanation:

I'm going to use Physics here for this concept of vectors. Here are some stipulations I have set for the problem (aka rules I set and then followed throughout the problem):

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