Answer:
6.3+1.1
Step-by-step explanation:
The communitive property of addition states that no matter what order of the numerical values the answer will be the same. hope this helps
2 2/3 ÷ 5/6 = 3.2 is the answer
What we have so far:
Kinetic energy = 0. The reason behind that is because the beam is not moving at a height of 40m.
Gavity, g = 9.8m/s²
Height = 40m
Potential energy = mgh; this is equal to 0 because m, stands for mass and in this problem, we do not have a value for the mass of the beam. Hence, 0 x 9.8m/s² x 40m = 0. Potential energy = 0.
Solution:
We will use the equation of Total energy:
TE = potential energy + kinetic energy
TE = 0 + 0
∴ TE = 0
The answer is: Assuming no air resistance, the total energy of the beam as it hits the ground is 0.
Answer:
B hope this helps :)
Step-by-step explanation:
