Two angles of a triangle measures 55° and 25° what is the measure of the third angle of the triangle

Mathematics

2 answers:

grigory [225]2 years ago

8 0

Answer:

100°

Step-by-step explanation:

55°+25°+third angle=180°(by angle sum property)

80°+third angle=180°

third angle=180°-80°

third angle=100°

Grace [21]2 years ago

6 0

Answer:

The measure of the third angle of the triangle would be 100°.

Step-by-step explanation:

25 + 55 + x = 180

80 + x = 180

x = 180 - 80

x = 100

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Which represents where f(x) = g(x)? A) f(4) = g(4) and f(0) = g(0) B) f(–4) = g(–4) and f(0) = g(0) C) f(–4) = g(–2) and f(4) =

saul85 [17]

Answer:

B. f(-4) = g(-4), and f(0) = g(0)

Step-by-step explanation:

We are given two functions that have been graphed already. The points on the coordinate plane where the curve of g(x) intercepts that of f(x), are the values of x for each function, that would give us the same output (y).

Thus, for f(x) intercepts g(x) at the point where x = -4, y = 4.

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2 years ago

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Blizzard [7]

Answer:

5x^2 + 12x -3 =0 ---------> solve by quadratic formula

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Step-by-step explanation:

1. 5x^2 + 12x -3 =0

The best way to solve this equation is quadratic formula as all the terms in the equation have coefficients it will be convenient to solve it through quadratic formula.

2. x^2 -4x = 8

The best way to solve this equation is by completing the square as the factors cannot be made directly.

3. 4x^2 -25 = 0

the best way to solve this equation is to solve by square root method as the 25 and 4 are perfect squares.

4. x^2-5x+ 6 = 0

The best way to solve this equation is to solve by factoring as it can clearly be seen that it is convenient to make factors ..

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What is the midpoint between the points (1, 4) and (-3, 2)?

emmasim [6.3K]

$\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ 1}}\quad ,&{{ 4}})\quad 
% (c,d)
&({{ -3}}\quad ,&{{ 2}})
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)
\\\\\\
\left(\cfrac{{{ -3}} + {{ 1}}}{2}\quad ,\quad \cfrac{{{ 2}} + {{ 4}}}{2} \right)$