Answer: 2.4 pounds of the type of nut that sells for $3.00/lb and 4.8 pounds of the type of nut that sells for $5.40/lb would be needed.
Step-by-step explanation:
Let x represent the number of pounds of the type of nut that sells for $3.00/lb that you would need.
Let y represent the number of pounds of the type of nut that sells for $5.40/lb that you would need.
You would like to have 7.2 lbs of a nut mixture. It means that
x + y = 7.2
The mixture would sell for $4.60/lb. It means that the cost of the mixture would be
4.6 × 7.2 = $33.12
This means that
3x + 5.4y = 33.12- - - - - - - - - 1
Substituting x = 7.2 - y Intl equation 1, it becomes
3(7.2 - y) + 5.4y = 33.12
21.6 - 3y + 5.4y = 33.12
- 3y + 5.4y = 33.12 - 21.6
2.4y = 11.52
y = 11.52/2.4
y = 4.8
x = 7.2 - y = 7.2 - 4.8
x = 2.4
Answer:
a is perpendicular to both b and c; the product of the slopes a and b or a and c is -1
Step-by-step explanation:
perpendicular slopes multiplied by each other would be -1
-1/3 * 3 for a and both other lines is -1
that means a is perpendicular to both b and c
Answer:
y= -3x - 2
You find this by looking at your x and y axis.
Hope this helps!
Answer:
1. 0.9648
2. 0.602
3. 0.0352
4. 0.398
Step-by-step explanation:
We solve using binomial probability
n = 15
P = 20% = 0.2
1. At least 1 is tight
= P(X>=1)
P(X>=1) = 1-p(X= 0)
= P(x=0)
= 15C0(0.20)⁰(1-0.20)^15-0
= 15C0(0.20)⁰(80)¹⁵
= 0.0352
P(x>=1) = 1-0.0352
= 0.9648
2.
More than 2 ties tight
P(X>2)
P(X>2) = 1-p(X<=2)
p(X<=2) = p(x=0) + p(x=1) + p(x=2)
= p(x=0) = 0.0352
p(x=1) = 15C1(0.20)¹(0.80)¹⁴
= 0.1314
p(x=2) = 15C2(0.20)²(0.80)¹³
= 0.2309
P(x>2) = 1-(0.0352+0.1314+0.2309)
= 0.602
3.
No ties is tight
P(X = 0)
= 15C0(0.20)⁰(0.80)¹⁵
= 0.0352
4.
At least 3 are not tight
This says that at most we have 3 to be too tight
= p(X<=2) = p(x=0) + p(x=1) + p(x=2)
= 0.0352+0.1319+0.2309
= 0.398
Answer:
APD=115
CPE=25
BPD=65
Step-by-step explanation:
I just took the test and i got it right.
