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Fantom [35]
3 years ago
8

Graph the line using a point and a slope. Write the equation of each line.

Mathematics
2 answers:
arsen [322]3 years ago
7 0

Answer:

  y = -1/2x -3

Step-by-step explanation:

The line perpendicular to one with a slope of 2 will have a slope that is the negative reciprocal of 2, that is, -1/2. The given point is the y-intercept of the required line, so we can write its equation directly in slope-intercept form:

  y = mx + b

where m is the slope (-1/2), and b is the y-intercept (-3). Your line is ...

  y = -1/2x -3

8090 [49]3 years ago
7 0

Answer:

y=-\frac{x}{2}-3

Step-by-step explanation:

If two lines having slopes m_1 and m_2 are perpendicular,

m_1\times m_2=-1

Thus, if the slope of the line perpendicular line with slope 2 is m,

Then,

m\times 2=-1\implies m = -\frac{1}{2}

Now, the equation of the line passes through (x_1, y_1) with slope m is,

y-y_1=m(x-x_1)

Hence, the equation of the line contain (0, -3) with slope -\frac{1}{2} is,

y+3=-\frac{1}{2}(x-0)

y=-\frac{1}{2}x-3

Graphing :

if x = 0, y = -3,

if y = 0, -\frac{x}{2}=3 ⇒ x = -6

Thus, by joining the points (0, -3) and (-6, 0) we will get the graph of the given line.

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4 0
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7 0
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