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kykrilka [37]
3 years ago
6

Tom has a large photo he wants to shrink to wallet-sized. It's width is 20 centimeters and it's len is 30 centimeters. If he wan

ts the width to be 5 centimeters what should the length be?
Mathematics
1 answer:
dsp733 years ago
5 0
We can use ratios, in other words, if one part of the photo is changed x times, how many times does the other part change?

We can set up the proportion as :
width 1 : length 1 = width 2 : length 2

20 : 30 = 5 : x

We do inverse multiplication, or multiply the outer with outer and inner with inner (W1 * L2 and L1 * W2)

20*x = 30*5
20x = 150
Divide all by 10
2x = 15
Divide all by 2 to isolate x
x = 15/2
x = 7.5cm
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Answer:

  You can use either of the following to find "a":

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Step-by-step explanation:

It looks like you have an isosceles trapezoid with one base 12.6 ft and a height of 15 ft.

I find it reasonably convenient to find the length of x using the sine of the 70° angle:

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That is not what you asked, but this value is sufficiently different from what is marked on your diagram, that I thought it might be helpful.

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Consider the diagram below. The relation between DE and AE can be written as ...

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Then the length EC is ...

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Now, we can find DC using the Pythagorean theorem:

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You can also make use of the Law of Cosines and the lengths x=AD and AC to find "a". (Do not round intermediate values from calculations.)

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