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2 years ago

11

Linda sells handmade jjewelry. She sells bracelets for $27.00, and the sales tax 6.5% of the sale price. Anout how much is the s

ales tax on the bracelet?
A. $1.62
B. $1.76
C. $28.76
D. $33.50

2 answers:

just olya [345]2 years ago

4 0

Answer:

b

Step-by-step explanation:

hope it helps

nexus9112 [7]2 years ago

3 0

Answer:

sales tax was $1.76

Step-by-step explanation:

$27 - 6.5% = 25.24

$27 - $25.24 = $1.76

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

(-5.4, 6.2)

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3 years ago

Mary sells to her father, robert, her shares in a corp for $55,000. the shares cost mary $80,000. how much loss may mary claim f

OverLord2011 [107]

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Mary Sells shares = $55,000

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3 years ago

18 Andy flies from the UK to Japan.

kotykmax [81]

Answer:

<u>Leila pays more</u> than Andy to fly from the UK to Australia.

Step-by-step explanation:

Given:

Andy flies from the UK to Japan.

His plane ticket costs £554.

Andy then flies from Japan to Australia.

His plane ticket costs 70 140 Japanese Yen.

The exchange rate is £1 = 140 Japanese Yen.

Leila flies from the UK to Australia.

Her plane ticket costs 1860 Australian dollars.

The exchange rate is 1 Australian dollar = £0.62.

<u>Now, to find Andy or Leila who pays more to fly from the UK to Australia.</u>

Andy flies from the UK to Japan.

His plane ticket costs = £554.

Andy then flies from Japan to Australia.

His plane ticket costs 70 140 Japanese Yen.

The exchange rate is £1 = 140 Japanese Yen.

So, by using conversion factor we convert Japanese Yen to £.

140 = £1

70140 = $70140\div 140=\£501.$

His plane ticket costs = £501.

Now, adding both the cost of tickets:

$501+554=\£1055.$

Andy total pays fly from the UK to Australia is £1055.

Now, to get the cost of plane ticket of Leila from the UK to Australia.

Her plane ticket costs 1860 Australian dollars.

The exchange rate is 1 Australian dollar = £0.62.

So, by using conversion factor:

1 Australian dollar = £0.62

1860 Australian dollar = $1860\times 0.62=\£1153.2$

Her plane ticket costs is £1153.2.

<u><em>As, we see that cost of plane ticket of Andy is £1055 and cost of plane ticket of Leila is £1153.2.</em></u>

<em>Thus, Leila pays more.</em>

Therefore, Leila pays more than Andy to fly from the UK to Australia.

4 0

3 years ago

The probability that a professor arrives on time is 0.8 and the probability that a student arrives on time is 0.6. Assuming thes

saul85 [17]

Answer:

a)0.08 , b)0.4 , C) i)0.84 , ii)0.56

Step-by-step explanation:

Given data

P(A) = professor arrives on time

P(A) = 0.8

P(B) = Student aarive on time

P(B) = 0.6

According to the question A & B are Independent

P(A∩B) = P(A) . P(B)

Therefore

${A}'$ & ${B}'$ is also independent

${A}'$ = 1-0.8 = 0.2

${B}'$ = 1-0.6 = 0.4

part a)

Probability of both student and the professor are late

P(A'∩B') = P(A') . P(B') (only for independent cases)

= 0.2 x 0.4

= 0.08

Part b)

The probability that the student is late given that the professor is on time

$P(\frac{B'}{A})$ = $\frac{P(B'\cap A)}{P(A)}$ = $\frac{0.4\times 0.8}{0.8}$ = 0.4

Part c)

Assume the events are not independent

Given Data

P $(\frac{{A}'}{{B}'})$ = 0.4

= $\frac{P({A}'\cap {B}')}{P({B}')}$ = 0.4

$P$ $({A}'\cap {B}')$ = 0.4 x P $({B}')$

= 0.4 x 0.4 = 0.16

$P({A}'\cap {B}')$ = 0.16

i)

The probability that at least one of them is on time

$P(A\cup B)$ = 1- $P({A}'\cap {B}')$

= 1 - 0.16 = 0.84

ii)The probability that they are both on time

P $(A\cap B)$ = 1 - $P({A}'\cup {B}')$ = 1 - $[P({A}')+P({B}') - P({A}'\cap {B}')]$

= 1 - [0.2+0.4-0.16] = 1-0.44 = 0.56

6 0

2 years ago