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Mariulka [41]
4 years ago
9

What is 16 1/2 x 2 1/2

Mathematics
2 answers:
uranmaximum [27]4 years ago
3 0
16 1/2 * 2 1/2 = 41.25
Ierofanga [76]4 years ago
3 0
Just to let you know half is the same as .5 so 16 1/2 would be 16.5 and 2 1/2 would be 2.5 so now 2.5x16.5=41.25 hope that this helps 
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Eric traveled to two cities on a single highway. The total distance one way was 200 miles. The distance from his original locati
drek231 [11]
<span>Equation (1) x + y = 200

Eauation (2) x = y - 40

x represents the distance from the original location to the firstt city

y represents the distance from the first city to the second city.

Solution:

(1) x + y = 200

(2) x - y = - 40
----------------------

2x = 200 - 40

2x = 160

x = 160 / 2

x = 80

x + y = 200 => y = 200 - x = 200 - 80 = 120

Therefore the solution (x,y) is (80,120)

Answer: the pair of coordinates that represents the solution (in miles) to this system of equations is (80, 120) </span>
6 0
4 years ago
Si caminara 1 2/3 alrededor de la jardinera triangular,Cuantos metros recorrería?
gavmur [86]

Answer:

0.0423333333 meters

Step-by-step explanation:

When you convert, you will receive the same result.

5 0
3 years ago
A class of 34 children has two more girls than triple the number of boys. How many girls are there in the class?
AveGali [126]
I think it’s 10 girls, if wrong, message me I’ll correct it
4 0
3 years ago
Draw a line representing the "run" and a line representing the "rise" of the line. State the slope of the line in simplest form.
Igoryamba

Answer:

The answer is "\bold{\frac{9}{13}}"

Step-by-step explanation:

In this question, the image file is missing, which is defined in the attached file. please find it.

\to raise= y_2-y_1

             =-1-(-10)\\\\=-1+10\\\\=9

\to run= x_2-x_1

          =9-(-4)\\\\=9+4\\\\=13

\to \text{formula for slope} =\frac{rise}{run} =\frac{9}{13}

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D%20-%5Cfrac%7Bx%7D%7B5%7D%20%2B%202%20%3D%200" id="TexFormula1" title="x^{2} -\frac
crimeas [40]

x^2 - x/5 + 2 = 0

Subtract 2 from both sides.

x^2 - x/5 = -2

Multiply all terms by 5.

5x^2 - x = -10

Add 10 to both sides.

5x^2 - x + 10 = 0

We can now apply the quadratic formula:

-b ± \frac{\sqrt{b^2 - 4ac} }{2a}

1 ± (√ 1 - 200) / 10

1 ± √-199 / 10

1 ± i√199 / 10

<h3><u>The solutions are equal to 1 + or - i times the square root of 199 divided by 10.</u></h3>
5 0
3 years ago
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