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Alex
2 years ago
12

A nutrition company is marketing a low-calorie snack brownie. A serving size of the snack is 3 brownies and has a total of 50 ca

lories.
(a) Determine how many calories 6 brownies would have.
(c) Determine how many calories 14 brownies would have. Round to the nearest calorie.
(b) Determine how many calories 21 brownies would have.
(d) If c represents the number of calories and b represents the number of brownies, write a proportional relationship involving c and b and solve it for c.
(e) Graph the proportional relationship you found
in part (d) on the grid shown. 300
200 100
(f) Using the graph, what is the smallest whole number of brownies a person would need to eat in order to consume 125 calories? Illustrate on your graph.
(g) Algebraicallydeterminethenumberofbrownies a person would need to eat in order to consume 300 calories.
Mathematics
2 answers:
klasskru [66]2 years ago
8 0

Answer:

Step-by-step explanation:

R

Alinara [238K]2 years ago
6 0

Answer:

I bolded all the answers because its a multipart problem

Step-by-step explanation:

Find the Calories per brownie

50/3

16.666666

A) 100

B)233

C) 350

D) C = 16.6666b

e) Your points should be at the following, (6,100) (12,200) (18,300)

Im gonna solve F mathmatically

125 = 16.66666b

125/16.66666

7.5

since they want whole numbers is

F) 8

G) 18 (Use the same way i used for 125, just switch 125 for 300)

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20\100 equivalent to 1\5<br> 5\8 equivalent to 9\10
Scilla [17]
20/100 is equivalent to 1/5.

Just divide by 20 on the top and bottom. (20/20)/(100/20)=1/5.
4 0
4 years ago
I dont understand this
hjlf
A or b because the equality is the radius squared. when you are looking at the equations you need to know the center of the circle so count 7 blocks in to the middle and make sure it's even on all sides. the equation is opposite positive and negative *if the center were 2,-5 then the equation would be (x-2)*(y+5)*
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IF YOU ANSER THIS ILL LITERALLY GIVE U 1$
VashaNatasha [74]

Answer: - 3/8

Step-by-step explanation:

3 0
3 years ago
Make a sketch of the region and its bounding curves. Find the area of the region. The region inside one leaf of r
Anastaziya [24]

The region inside one leaf of r the area of the region is pi.20.

r =cos5θ

cos5θ =0

5θ=pi/2 ,5θ=3pi/2

θ=pi/10,θ=3pi/10

area of one leaf = ∫[pi/10 to 3pi/10](1/2)r2dθ

= ∫[pi/10 to 3pi/10](1/2)(cos5θ)2dθ

= ∫[pi/10 to 3pi/10](1/4)(1+cos10θ)dθ

=[pi/10 to 3pi/10](1/4)(θ+ (1/10)sin10θ)

=(1/4)((3pi/10)+ (1/10)sin3pi) -(1/4)((pi/10)+ (1/10)sinpi)

=(1/4)(3pi/10)  -(1/4)(pi/10)

=(1/4)(2pi/10)  

=pi/20

area of one leaf =pi.20.

Region area (calculus) Region area. The non-negative function given by y = f(x) represents a smooth curve on the closed interval [a, b].The area through the curve of f(x), the x-axis, and the perpendicular lines x = a and x = b The bounding region shown in Figure 1 is given by.

Learn more about the area of the region here: brainly.com/question/19053586

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4 0
1 year ago
Solve for p. 2(p + 3) = 20
guapka [62]

Answer:

p=7

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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