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3 years ago

15

At an animal shelter there are 15 dogs, 12 cats, 3 snakes and 5 parakeets. What percentage of cats is the number of dogs?

2 answers:

suter [353]3 years ago

8 0

Answer:

125%

Step-by-step explanation:

15/12 = 1.25 then you move the decimal over 2 places.

Gwar [14]3 years ago

6 0

Answer:

The percent of the number of cats and the number or dogs is 80%.

Step-by-step explanation:

At the shelter there are 15 dogs 12 cats three snakes and five parakeets.

Total animals are = 15+12+3+5=35

We have to tell what percent of the number of cats is the number of dogs.we have 12 cats and 15 dogs, so required percentage is : 80% = (12 divided by 15) times 100

Therefore, the percent of the number of cats is the number of dogs is 80%.

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wlad13 [49]

The equation is 24=23.50+0.25r

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3 years ago

I need help with this is it yes or no?

n200080 [17]

Answer:

No.

Step-by-step explanation:

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3 years ago

Charles has eight different winter scarves, and he wears three at a time. How many different ways can Charles wear three scarves

jenyasd209 [6]

Answer:

Ans= 6720 ways

Step-by-step explanation:

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6 0

2 years ago

A, B, C, D, E and F are points on a circle. put crosses on the ends of the line that is a diameter of the circle

Step2247 [10]

9514 1404 393

Answer:

AD is the diameter

Step-by-step explanation:

Angles in a triangle have a sum of 180°, so inscribed angle B is 80° and inscribed angle E is 90°.

An inscribed angle subtends an arc that is twice its measure, so arcs ABD and AED are both 180°. That makes chord AD a diameter.

Points A and D need your cross markings. AD is a diameter of the circle.

3 0

3 years ago

A Mexican restaurant sells quesadillas in two sizes: a "large" 10 inch-round quesadilla and a "small" 5 inch-

elena-14-01-66 [18.8K]

Answer:

Half of the 10-inch quesadilla is greater than the entire 5-inch quesadilla

Step-by-step explanation:

we know that

The area of a circle is equal to

$A=\pi r^2$

where

r is the radius

step 1

Find the area of the 10 inch-round quesadilla

we have

$D=10\ in$

$r=10/2=5\ in$

substitute

$A=\pi (5)^2$

$A=25\pi\ in^2$

step 2

Find the area of the 5 inch-round quesadilla

we have

$D=5\ in$

$r=5/2=2.5\ in$

substitute

$A=\pi (2.5)^2$

$A=6.25\pi\ in^2$

step 3

Which is larger, half of the 10-inch quesadilla or the entire 5-inch quesadilla?

Compare

half of the 10-inch quesadilla is equal to ----> $\frac{1}{2}(25\pi)=12.5\pi\ in^2$

the entire 5-inch quesadilla ----> $6.25\pi\ in^2$

therefore

Half of the 10-inch quesadilla is greater than the entire 5-inch quesadilla

3 0

3 years ago