Question

Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth.

Answer 1

A ) h = -16 t² + 135 t + 76
Let : h = 0
0 = - 16 t² + 135 t + 76
B ) t 1/2 = (-b+/- √ ( b² - 4 ac ) / ( 2 a )
t 1/2 = (-135 - √(18,225 + 4,864))/ (-32) = ( - 135 - 151.95) / (- 32)=
= (-286.95) / (- 32) = 9.967 ≈ 9.0 s ( other solution is negative )
Answer:
2)  0 = -16 t² + 135 t + 76;  9 s 

Answer 2

Answer:

The answer is 2.) $0=-16t^{2}+135t+76;9 s$

Step-by-step explanation:

Given initial velocity=135 ft/s

& cliff=76 foot

Given quadratic equation

$0=-16t^{2}+vt+c$

⇒   $0=-16t^{2}+135t+76$                    (let h=0 it is given)

⇒   $t=\frac{-135\pm\sqrt ((135)^{2}-4(-16)(76))}{2(-16)}$

⇒   $t=\frac{-135\pm151.951}{-32}$

⇒    t=8.96≈9 s (the other root is negative)

Hence, rocket will take 9 s to hit the ground after launched.