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enot [183]
4 years ago
11

Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth.

Mathematics
2 answers:
DaniilM [7]4 years ago
7 0
A ) h = -16 t² + 135 t + 76
Let : h = 0
0 = - 16 t² + 135 t + 76
B ) t 1/2 = (-b+/- √ ( b² - 4 ac ) / ( 2 a )
t 1/2 = (-135 - √(18,225 + 4,864))/ (-32) = ( - 135 - 151.95) / (- 32)=
= (-286.95) / (- 32) = 9.967 ≈ 9.0 s ( other solution is negative )
Answer:
2)  0 = -16 t² + 135 t + 76;  9 s 

drek231 [11]4 years ago
6 0

Answer:

The answer is 2.) 0=-16t^{2}+135t+76;9 s

Step-by-step explanation:

Given initial velocity=135 ft/s

& cliff=76 foot

Given quadratic equation

0=-16t^{2}+vt+c

⇒   0=-16t^{2}+135t+76                    (let h=0 it is given)

⇒   t=\frac{-135\pm\sqrt ((135)^{2}-4(-16)(76))}{2(-16)}

⇒   t=\frac{-135\pm151.951}{-32}

⇒    t=8.96≈9 s (the other root is negative)

Hence, rocket will take 9 s to hit the ground after launched.


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