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3 years ago

Stella needed to get her computer fixed. She took it to the repair store. The technician

Mathematics

1 answer:

zhuklara [117]3 years ago

5 0

9514 1404 393

Answer:

$35 per hour

Step-by-step explanation:

The total charge is the sum of costs of parts and labor. If h is the cost of a labor hour, then we have ...

188.75 = 75 + 3.25h

113.75 = 3.25h . . . . . . . . subtract 75

113.75/3.25 = h = 35 . . . divide by the coefficient of h

The cost of labor, per hour, is $35.

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Darren wins a coupon for $4 off the lunch special for each of five days he pays $75 for his 5 lunch specials write and solve an

Valentin [98]

The original price for one lunch special is $19.

Explanation

The original price for one lunch special is 'p' dollar.

He wins a coupon for $4 off for each of five days. That means , he needs to pay $(p-4)$ dollar each day.

So, the total amount needed to pay for 5 days $= 5(p-4)$ dollar

Given that, he pays $75 for his 5 lunch specials. So the equation will be.....

$5(p-4)= 75\\ \\ 5p-20=75\\ \\ 5p= 75+20\\ \\ 5p= 95\\ \\ p=\frac{95}{5}=19$

So, the original price for one lunch special is $19.

8 0

3 years ago

A company produces and sells widgets and gizmos. In January the company sold 350 items for a total of $9,000. If each widget sol

iren [92.7K]

Answer:

The company sold 100 widgets and 250 gizmos.

Step-by-step explanation:

Let $x_1$ be the number of widgets sold and $x_2$ be the number of gizmos sold.

We are told that the company sold 350 items. We can represent this information in an equation as:

$x_1+x_2=350...(1)$

We have been given that a each widget sold for $35 and each gizmo sold for $22. The company sold 350 items for a total of $9,000.

We can represent this information in an equation as:

$35x_1+22x_2=9,000...(2)$

From equation (1), we will get:

$x_2=350-x_1$

Substitute this value in equation (2):

$35x_1+22(350-x_1)=9,000$

$35x_1+7,700-22x_1=9,000$

$13x_1+7,700=9,000$

$13x_1+7,700-7,700=9,000-7,700$

$13x_1=1,300$

$\frac{13x_1}{13}=\frac{1,300}{13}$

$x_1=100$

Therefore, the company sold 100 widgets.

Substitute $x_1=100$ in equation (1):

$100+x_2=350$

$100-100+x_2=350-100$

$x_2=250$

Therefore, the company sold 250 gizmos.

3 0

3 years ago

Read 2 more answers

As a basketball is bounced, the motion is parabolic. In the graph above, y = 0 represents hand level for a basketball player. Fi

WITCHER [35]

Answer:

A on edge2020

Step-by-step explanation:

3 0

3 years ago

A 10-foot ladder is leaning against a vertical wall. If the bottom of the ladder is being pulled away from the wall at the rate

Alex777 [14]

Answer:

The area is changing at 15.75 square feet per second.

Step-by-step explanation:

The triangle between the wall, the ground, and the ladder has the following dimensions:

H: is the length of the ladder (hypotenuse) = 10 ft

B: is the distance between the wall and the ladder (base) = 6 ft

L: the length of the wall (height of the triangle) =?

dB/dt = is the variation of the base of the triangle = 9 ft/s

First, we need to find the other side of the triangle:

$H^{2} = B^{2} + L^{2}$

$L = \sqrt{H^{2} - B^{2}} = \sqrt{(10)^{2} - B^{2}} = \sqrt{100 - B^{2}}$

Now, the area (A) of the triangle is:

$A = \frac{BL}{2}$

Hence, the rate of change of the area is given by:

$\frac{dA}{dt} = \frac{1}{2}[L*\frac{dB}{dt} + B\frac{dL}{dt}]$

$\frac{dA}{dt} = \frac{1}{2}[\sqrt{100 - B^{2}}*\frac{dB}{dt} + B\frac{d(\sqrt{100 - B^{2}})}{dt}]$

$\frac{dA}{dt} = \frac{1}{2}[\sqrt{100 - B^{2}}*\frac{dB}{dt} - \frac{B^{2}}{(\sqrt{100 - B^{2}})}*\frac{dB}{dt}]$

$\frac{dA}{dt} = \frac{1}{2}[\sqrt{100 - 6^{2}}*9 - \frac{6^{2}}{\sqrt{100 - 6^{2}}}*9]$

$\frac{dA}{dt} = 15.75 ft^{2}/s$

Therefore, the area is changing at 15.75 square feet per second.

I hope it helps you!

5 0

3 years ago

The vertices of a triangle are P(–8, 6), Q(1, –3), and R(–6, –3). Name the vertices of

xz_007 [3.2K]

The refrection of a point or set of points across the line y = x will result in a point or set of points whose coordinates are the interchange of the x-value and the y-value of the original point or set of points.

Given that the vertices of a triangle are P(-8, 6), Q(1, -3) and R(-6, -3), the vertices of the triangle formed by the refrection Ry=x(ΔPQR) are P'(6, -8), Q'(-3, 1) and R'(-3, -6).

5 0

3 years ago