Trig please help.

Mathematics

1 answer:

asambeis [7]3 years ago

4 0

Answer:

24 and 40

Step-by-step explanation:

The area of a triangle is given by the following formula:

$A=\frac{1}{2}bh$

where:

A is the area

b is the base of the triangle

h is the height

In this problem, the 1st triangle has:

b = 6 is the base

h = 8 is the height

Therefore, the area of the triangle is:

$A_1=\frac{1}{2}(6)(8)=24$

The second triangle of this problem has instead:

b = 8 is the base

h = 10 is the height

Therefore, the area of the triangle is:

$A_2=\frac{1}{2}(8)(10)=40$

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Virty [35]

Dy/dx=25, 35, 45, 55

d2y/dx2=10,10,10 (this constant just proves that it is a quadratic relation)

Now we can set up a system of equations for ax^2+bx+c

16a+4b+c=80, 9a+3b+c=45, 4a+2b+c=20 getting differences

7a+b=35, 5a+b=25 and again

2a=10, a=5, making 7a+b=35 become:

7(5)+b-35, b=0, making 4a+2b+c=20 become:

4(5)+2(0)+c=20, c=0 so

y=5x^2

So the constant of variation for this quadratic is 5.

6 0

3 years ago

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