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Alja [10]
2 years ago
5

Find the area of the irregular figure. I don’t know this I need help.

Mathematics
1 answer:
Shkiper50 [21]2 years ago
4 0

Answer:

11 in.²

Step-by-step explanation:

you can divide the shape into 2 rectangles and then you solve for the 2 rectangles and then you add them up.

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<u>G</u><u>iven </u><u>:</u><u>-</u>

  • A right angled triangle with two sides 10cm and 9cm .

<u>To </u><u>Find</u><u> </u><u>:</u><u>-</u>

  • The value of theta .

<u>Solution</u><u> </u><u>:</u><u>-</u>

At angle theta , 9cm side will be considered as the perpendicular and 10cm side will be hypotenuse . So , as we know that ;

\longrightarrow sin\theta =\dfrac{perpendicular}{hypotenuse}

Substituting the respective values,

\longrightarrow sin\theta =\dfrac{9cm}{10cm}

Simplify,

\longrightarrow sin\theta= 0.9

Take arcsin both sides ,

\longrightarrow \theta =sin^{-1}(0.9)

\\\longrightarrow\underline{\underline{\theta = 64.15^o }}

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