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3 years ago

Can someone help me with the top problem

Mathematics

2 answers:

Yanka [14]3 years ago

5 0

a: y intercept

b: neither

c: x intercept

d: both

e: x intercept

3241004551 [841]3 years ago

4 0

A) x intercept

B) both

C)y intercept

D) both

E) x intercept

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832,651,097 help me<br> With problem #3

Alborosie

Answer:

Hi :D

Nearest hundred thousand: 832,650,000

Nearest thousand: 832,651,000

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Nearest hundred: 832,651,100

Hope this helps!

Sahkfam (:

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4 years ago

Who wants brainlest?

sp2606 [1]

It doesn’t let me type the correct answer i’m confused

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3 years ago

Read 2 more answers

A toy airplane climbs 30 vertical feet while traveling 50 feet horizontally. A toy helicopter climbs 20 feet while traveling 40

maw [93]

Answer:

The Slop of airplane is greater than slop of helicopter

Step-by-step explanation:

Given as

Vertical height of toy airplane = 30 feet

The horizontal distance is 50 feet

Let, The slop of toy airplane is H

Now by Pythagoras theorem

H ² = P² + B²

Or, H² = 30² + 50² = 900 + 2500

Or, H² = 3400 feet

SO, Slop = H =√3400 = 58.30 feet

Again

Vertical height of toy helicopter = 20 feet

The horizontal distance is 40 feet

Let, The slop of toy helicopter is h

Now by Pythagoras theorem

H ² = P² + B²

Or, h² = 20² + 40² = 400 + 1600

Or, h² = 2000 feet

SO, Slop = h =√2000 = 44.72 feet

Since $H> h$

Hence The Slop of airplane is greater than slop of helicopter Answer

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4 years ago

Read 2 more answers

If x^6=60 and w^10=20, what is x^12×w^-10? A. 36, B. 60, C. 180 or D. 360

tigry1 [53]

Answer:

$x^{12} w^{-10}$

And we can find this rewriting the expression in terms of the info given and we got:

$x^{12} w^{-10} = (x^6)^2 (w^{10})^{-1}$

And replacing we got:

$x^{12} w^{-10} = (60)^2 (20)^{-1}= \frac{60^2}{20}= 180$

And the best option would be:

C. 180

Step-by-step explanation:

For this case we know that:

$x^6, w^{10} = 20$

And we want to find the value for:

$x^{12} w^{-10}$

And we can find this rewriting the expression in terms of the info given and we got:

$x^{12} w^{-10} = (x^6)^2 (w^{10})^{-1}$

And replacing we got:

$x^{12} w^{-10} = (60)^2 (20)^{-1}= \frac{60^2}{20}= 180$

And the best option would be:

C. 180

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3 years ago

Which two integers have a product of -120 and a sum of -2?

djverab [1.8K]

Answer:

The product of two integers is #75# and their sum is #-28#. i dont know if this is helpful

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3 years ago