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3 years ago

Between which two consecutive numbers does √300 fall

Mathematics

1 answer:

Musya8 [376]3 years ago

6 0

Answer:

The number is between 17 and 18

Step-by-step explanation:

Given

$Digit = \sqrt{300}$

Required

Determine the range

Start by solving square root

$Digit = \sqrt{300}$

$Digit = 17.3205080757$

Next, we approximate the resulting digit, down; This gives the lower bound.

$Lower\ Bound = 17$ -- When approximated

Add 1 to the lower bound, this given upper bound

$Upper\ Bound = 18$

<em>Hence, the number is between 17 and 18</em>

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klemol [59]

Answer:

r = radius of circle

Step-by-step explanation:

The circumference of a circle is given by :

C = 2πr

Where

r is the radius of the circle

In this problem, we need to say that what does r represents in the given formula. It means we can say that r stands for the radius of the circle.

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2 years ago

A department store buys 500 shirts at a cost of $3,500 and sells them at a selling price of $10 each. Find the percent markup.

Ratling [72]

Answer: 30 percent.

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2 years ago

Help a brother out!!! Math prom worth 20!! And explain please

Reil [10]

A.

ratio 1 to 1

alright
find the distance between the x values and the y values and seperate each into that ratio
1:1
A to B is (6,12) to (15,-4)
disatnce from 6 to 15 is 9, ratio would be 4.5:4.5=1:1
distance from 12 to -4 is 16, ratio would be 8:8=1:1
so the point would be (4.5,8)

b.
5:2
5+2=7
alright
A to C
(6,12) to (20,12)
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distance from 12 to 12=0, so same coordinate
the point is (10,12)

c.
2+3=5

C to B
C is (20,12) and B is (15,-4)
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3 years ago

Which formula can be used to find the nth term of a geometric sequence where the fifth term is 1/6 and the common ratio is 1/4?

OlgaM077 [116]

Answer:

$a_n = 16(\frac{1}{4})^{n - 1}$

Step-by-step explanation:

Given:

Fifth term of a geometric sequence = $\frac{1}{16}$

Common ratio (r) = ¼

Required:

Formula for the nth term of the geometric sequence

Solution:

Step 1: find the first term of the sequence

Formula for nth term of a geometric sequence = $ar^{n - 1}$ , where:

a = first term

r = common ratio = ¼

Thus, we are given the 5th term to be ¹/16, so n here = 5.

Input all these values into the formula to find a, the first term.

$\frac{1}{16} = a*\frac{1}{4}^{5 - 1}$

$\frac{1}{16} = a*\frac{1}{4}^{4}$

$\frac{1}{16} = a*\frac{1}{256}$

$\frac{1}{16} = \frac{a}{256}$

Cross multiply

$1*256 = a*16$

Divide both sides by 16

$\frac{256}{16} = \frac{16a}{16}$

$16 = a$

$a = 16$

Step 2: input the value of a and r to find the nth term formula of the sequence

nth term = $ar^{n - 1}$

nth term = $16*\frac{1}{4}^{n - 1}$

$a_n = 16(\frac{1}{4})^{n - 1}$

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2 years ago

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7nadin3 [17]

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