Between which two consecutive numbers does √300 fall

Mathematics

1 answer:

Musya8 [376]3 years ago

6 0

Answer:

The number is between 17 and 18

Step-by-step explanation:

Given

$Digit = \sqrt{300}$

Required

Determine the range

Start by solving square root

$Digit = \sqrt{300}$

$Digit = 17.3205080757$

Next, we approximate the resulting digit, down; This gives the lower bound.

$Lower\ Bound = 17$ -- When approximated

Add 1 to the lower bound, this given upper bound

$Upper\ Bound = 18$

Hence, the number is between 17 and 18

You might be interested in

The function g(x) = 8x2 – 48x + 65 written in vertex form is g(x) = 8(x – 3)2 – 7. What is the vertex of g(x)?

maksim [4K]

The answer is (3, -7). If the function is written in the form y = a(x – h)^2 + k, the vertex will be (h, k). Let's write the function 8x^2 – 48x + 65 in the form of a(x – h)^2 + k. g(x) = 8x^2 – 48x + 65. g(x) = 8x^2 – 48x + 72 - 72 + 65. g(x) = (8x^2 – 48x + 72) - 7. g(x) = (8 * x^2 – 8 * 6x + 8 * 9) - 7. g(x) = 8(x^2 - 6x + 9) - 7. g(x) = 8(x - 3)^2 - 7. The function is now in the form a(x – h)^2 + k, where a = 8, h = 3, and k = -7. Thus, the vertex is (3, -7).

4 0

3 years ago

Read 2 more answers

Shirts are 5% off. The original price of one shirt is $15. What is the total cost, in dollars, of a shirt at the sale price, inc

Juliette [100K]

Answer:

$15.75

Step-by-step explanation:

$\frac{y}{15} :\frac{5}{100}$