Answer:
π
V-foam = 4r³( 2 - ----- )
3
Step-by-step explanation:
Let the radius of the sphere be r. Then the volume of the sphere is
V = (4/3)(π)(r³).
Next, recognize that the side length of the cube is 2r, and that the volume of the cube is thus
V = (2r)³, or 8r³.
Then the volume of the foam is equal to the volume of the cube less the volume of the sphere:
V-foam = 8r³ - (4/3)(π)(r³). This could be factored into
π
V-foam = 4r³( 2 - ----- )
3
Answer:
538.3
Step-by-step explanation:
First of all find the area of the rectangle
L*W
15*30
450
Now find the area of semi circle
1/2
Since radius is half a diameter divided 15 by 2=7.5
1/2
7.5 times 7.5= 56.25
1/2*3.14*56.25
56 times 3.14 is 176.625 now multiply 176.625 by 1/2
Answer is 88.3125
Now add 450 to 88.3125
Final answer: 538.3125
1. 0
2. 32.6
3. 326
4. 3260
considering i’m not the best at maths, can someone check these for me?
The answer is
<span>
The IQR is the best measure of variability because the distribution has an outlier.
Hoped I Helped I did the test</span>
