1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
stealth61 [152]
3 years ago
15

Cora ran 5 miles last month and will run ½ miles per week for the next 2.5 months. Hana ran 3 miles last month and will run ¾ mi

les per week for the next 2.5 months.
Mathematics
1 answer:
Mashutka [201]3 years ago
5 0

Step-by-step explanation:

if Cora runs 1/2 mile per week and x is the number of weeks, then she will run 5+1/2x.

then determine how many weeks are in two and a half months ( depends on which month it is as there are less weeks in February than in January) but we could estimate 6.

for hana you will have 3+ 3/4x

first equation is y=5+ 1/2x and then plug 6 in for x to solve for y. the second equation is y=3+ 3/4x and plug in 6

You might be interested in
How many solutions are there to the equation below?
Nata [24]
The answer is c because ther is only one value for x which is -2.5
6 0
3 years ago
Read 2 more answers
HELP PLZ GOD BLESS YOUR GRADES
fgiga [73]

Answer:

its A

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
-HELP QUICK!!- What is the distance from P to Q? <br><br> A P E X
skad [1K]

Answer:

might be 7

Step-by-step explanation:

count the rise and run from Q to P. count up 3 and right 4.

5 0
3 years ago
A consumer organization estimates that over a​ 1-year period 20​% of cars will need to be repaired​ once, 8​% will need repairs​
Sladkaya [172]

Answer:

Probability that a car need to be repaired​ once = 20% = 0.20

Probability that a car need to be repaired​ twice = 8% = 0.08

Probability that a car need to be repaired​ three or more = 2% = 0.02

a) If you own two​ cars what is the probability that  neither will need​ repair?

Probability that a car need to be repaired​ once , twice and thrice or more= 0.20+0.08+0.02=0.3

Probability that car need no repair = 1-0.3=0.7

Neither car will need repair=0.7 \times 0.7=0.49

​b) both will need​ repair?

Probability both will need​ repair = 0.3 \times 0.3=0.09

c)at least one car will need​ repair

Neither car will need repair=0.7 \times 0.7=0.49

Probability that at least one car will need​ repair= 1-0.49 = 0.51

6 0
3 years ago
Please help and show work!!
Advocard [28]

1/3x + y = -2

-1/3x         -1/3x

y = -1/3x-2

4 0
4 years ago
Other questions:
  • What is 3.56 as a fraction
    9·2 answers
  • I need help ASAP please
    15·1 answer
  • How many golf balls will fit into a suitcase
    7·1 answer
  • Passengers using New York's MetroCard system must swipe the card at a rate between 10 and 40 inches per second, or else the card
    5·2 answers
  • Help i need help i can't figure this out​
    6·2 answers
  • Suppose a deck of cards contains 13 cards:
    13·1 answer
  • Explain why angle “a” must be 135
    9·1 answer
  • Help ASAP pls I’m not sure if it is -10 or -5
    5·1 answer
  • Tomas got 3/4 of the questions correct on an exam. There were 24 questions on the exam. What number of questions did Tomas get c
    14·1 answer
  • Find the lengths of the missing sides. Write your answers as integers or as decimals rounded to the nearest tenth.
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!