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stealth61 [152]
2 years ago
15

Cora ran 5 miles last month and will run ½ miles per week for the next 2.5 months. Hana ran 3 miles last month and will run ¾ mi

les per week for the next 2.5 months.
Mathematics
1 answer:
Mashutka [201]2 years ago
5 0

Step-by-step explanation:

if Cora runs 1/2 mile per week and x is the number of weeks, then she will run 5+1/2x.

then determine how many weeks are in two and a half months ( depends on which month it is as there are less weeks in February than in January) but we could estimate 6.

for hana you will have 3+ 3/4x

first equation is y=5+ 1/2x and then plug 6 in for x to solve for y. the second equation is y=3+ 3/4x and plug in 6

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Simplify the expression.
gizmo_the_mogwai [7]
Always simplify expressions in the order of PMDAS
(Parenthesis, Multiplication, Division, Addition, Subtraction)
(4-1) = (3)
[(1+6) + 2] = [7 + 2] = (9)
(3)x(9) = 27
The answer is 27
8 0
3 years ago
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denis-greek [22]

Answer:

A

Step-by-step explanation:

PEMDAS means always do parenthesis first, which means subtract 10-6=4

6 0
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patriot [66]
The answer would be C because the y-intercept tells you what y when x is 0. In this case, y is wage and x is years of experience. So, if you have 0 years of experience you get an average of 7.25 dollars per hour, which is C.
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3 years ago
Hi, i need to know the work and answer to this. thanks!
Nesterboy [21]

Answer:

432 in^2

Step-by-step explanation:

in similar quadrilaterals, the first point of one quad. corresponds to the first point of the other quad, so in this case UA corresponds with CH.

since CH is 3/4 the length of UA, we can also assume that the other sides in ZUCH are 3/4 the length of their corresponding sides in SQUA.

even though we don't know what quadrilateral SQUA and ZUCH are, we know the area of SQUA is 9/16 times less than ZUCH.

want some proof?

lets say SQUA and ZUCH are rectangle/square

ZUCH: 4X4 = 16

SQUA: 3X3 = 9

now lets say they are trapezoids. We will set ZUCH 2nd base to 8 and height to 16, therefore SQUA bases will be 3 and 6, and the height will be 12 (multiply ZUCH lengths by 3/4)

ZUCH = (b1+b2)(h)/2 = (4+8)(16)/2 = 96

SQUA = (b1+b2)(h)/2 = (3+6)(12)/2 = 54

simplify 96/54 = 16/9

now we can multiply 243 by our factor 16/9 to find the area of SQUA.

243 * 16/9 = 432 in^2

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3 years ago
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4x^2-5x-21 is of the form ax^2+bx+c, a quadratic equation.

so b in this case is -5
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3 years ago
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