Answer:
The answer is D.) Mercury
Answer:
i have not a clue in the world lol
Both will contain the sugar ribose and the base uracil
Answer:
C. An approximately three-to-one ratio of black to brown coated mice in F2 is accounted for by the black allele being dominant over the brown allele
Explanation:
Assuming the black genotype is BB and the brown genotype is bb.
At F1:
BB x bb = All Bb (black)
At F2:
Bb x Bb = BB (black), 2Bb (Black), bb (brown)
Th ratio of black to brown is 3:1
961 black : 317 brown is approximately 3:1.
Hence, the correct option is C.
<em>An approximately three-to-one ratio of black to brown coated mice in F2 is accounted for by the black allele being dominant over the brown allele</em>
