Answer: The correct option is A, itis the product of the initial population and the growth factor after h hours.
Explanation:
From the given information,
Initial population = 1000
Increasing rate or growth rate = 30% every hour.
No of population increase in every hour is,

Total population after h hours is,

It is in the form of,

Where
is the initial population, r is increasing rate, t is time and [tex(1+r)^t[/tex] is the growth factor after time t.
In the above equation 1000 is the initial population and
is the growth factor after h hours. So the equation is product of of the initial population and the growth factor after h hours.
Therefore, the correct option is A, itis the product of the initial population and the growth factor after h hours.
Answer:

Step-by-step explanation:
Given:
The expression to expand is given as:

Let us expand the first two binomials of the given expression using FOIL method.
The FOIL method states that:


Now, let us multiply the result with the remaining binomial. Multiplying each term of the trinomial with each term of the binomial, we get:

Therefore, the equivalent expression after expanding is given as:

The answer would be 9. 9x3=27 and 9x4=36. Although 3 fits into both, 9 is the BIGGER number that also fits into both of the numbers shown in the problem.