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Studentka2010 [4]
2 years ago
7

Multiply(2.3x10^-5)(3.1x10^12)

Mathematics
2 answers:
Andrej [43]2 years ago
7 0

Answer: 71300000

Step-by-step explanation:

yan [13]2 years ago
6 0

Answer:

7.13 x 10^7.

Step-by-step explanation:

2.3x10^-5)(3.1x10^12

= 2.3x3.1 x 10^-5 x 10^12

= 7.13 x 10^(-5+12)

= 7.13 x 10^7.

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Stu hiked a trail at an average rate of 3 miles per hour. He ran back on the same trail at an average rate of 5 miles per hour.
Andrews [41]
3t = 5(3-t)
3t = 15 - 5t
3t + 5t = 15
8t = 15
t = 15/8
t = 1 7/8 

7/8 * 60 mins = 52.50 minutes

t = 1 hour and 52.5 minutes

It took Stu 1 hour and 52.5 minutes to hike the trail one way.
3 0
3 years ago
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The current average property value is two-sevenths more than last year’s average value. What was last year’s average property va
Ilya [14]

Answer:

63350

Step-by-step explanation:

Given that the current average property value is two-sevenths more than last year’s average value.

Let x be the last year's average property

Then we have as per the given information this year property value

=x+\frac{2}{7} x

Equate this to

x+\frac{2}{7} x=81450\\9x = 7(81450)\\x = 7(9050)\\x= 63350

6 0
3 years ago
The ages of the Oscar-winners for best actor and actress for the years 1970 through 1990 are given below: Women: 34, 34,26,37,42
Artemon [7]

Answer:

See explanation below.

Step-by-step explanation:

Numerical way

We can calculate the mean and the standard deviation from a sample with the following formulas:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

s= \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}

We have the following dataset for women: 34,34,26,37,42,41,35,31,41,33,30,74,33,49,38,61,21,41,26,80,72

And the mean and deviation are:

\bar X_F = 41.857

s_F = 16.399

We can calculate the median ordering the data like this:

21,26,26,30,31,33,33,34,34,35,37,38,41,41,41,42,49,61,72,74,80

And the median would be on the 11 position of the data ordered, for this case is:

median_F = 37

Minimum_F = 21 , Maximum_F = 80

And the range is given by: Range_F = 80-21=59

We can also calculate the coefficient of variation given by:

\hat{CV} =\frac{s}{\bar X} = \frac{16.399}{41.857}=0.392

We have the following dataset for men:

43, 40,48,48,56,38,60,32,40,42,37,76,39,55,45,35,61,33,51,32,42

And the mean and deviation are:

\bar X_M = 45.381

s_M = 11.218

We can calculate the median ordering the data like this:

32, 32,33,35,37,38,39,40,40,42,42,43,45,48,48,51,55,56,60,61,76

And the median would be on the 11 position of the data ordered, for this case is:

median_M = 42

Minimum_M = 32 , Maximum_F = 76

And the range is given by: Range_M = 76-32=44

We can also calculate the coefficient of variation given by:

\hat{CV} =\frac{s}{\bar X} = \frac{11.218}{45.381}=0.247

We se that the mean for the male groups is higher than the mean for female group. The deviation is higher for the female group comapred to the male group. We have more variation for the female group as we can see on the range and the coeffcient of variation.

Graph

We can see the histograms for each group on the figures attached.

As we can see the histogram for males is skewed to the right with the median lower than the mean.

By the other hand the histogram for the female group seems to be skewed to the right also but with missing values on the interval 50-60, for this reason we have more variation compared to the male group.

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omeli [17]
M+p=475
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