Answer:4x>2+3x+5
Step-by-step explanation:
12x>3+8x>2+9x>2+21x+10
12x>3+8x>2+9x>2+6x+15×10
4x^2(3x+2)+9x^2×6x
4x^2(3x+2)+3x(3x+2)+15x+10
4x^2(3x+2)3x(3x+2)+5(3x+2)
Cancel
3x+2(4×^2+3x+5)
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3x+2
4x^2+3x+5
- An isosceles triangle ABC
- AD is a bisector of ∠A
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- By ASA criteria ∆ABD congurant to ∆ADC
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- By CPCT ( corresponding parts of congurant triangle )
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Answer:
Step-by-step explanation:
mid point = [(a1 + a2)/2 , (b1 + b2)]
(a1,b1) = first point
(a2,b2) = end point
Using all x coordinates
(a1 + a2)/2 = 1
(-1 + a2)/2 = 1
-1 + a2 = 2
a2 = 3
Using all y coordinates
(b1 + b2)/2 = -1
(-3 + b2)/2 = -1
-3 + b2 = -2
b2 = -1
thus end coordinate = (3, -1)
Answer:
r = 3
Step-by-step explanation:
x^2 + 6x + y^2 - 8y = - 16
Take half the linear term and square it.
x^2 + 6x + (3)^2 + y^2 - 8y + (-4)^2 = - 16
Add the squared amounts to the right.
x^2 + 6x + 9 + y^2 - 8y + 16 = - 16 + 9 + 16
Combine on the right.
x^2 + 6x + 9 + y^2 - 8y + 16 = 9
Represent the 2 quadratics as perfect squares.
(x + 3)^2 + y - 4)^2 = 9
The radius is the square root of 9 which is 3
