Area of the sector = 1/2 * r^2 * theta where theta is the angle subtended by the arc at the center ( in radians)
In this case m < theta = 360 - 235 = 125 degrees or 2.182 radians
So, the area of shaded area = 1/2 * 20^2 * 2.182 = 436.4 in^2
$1235-$800=$435 thus the I which is the simple interest
:I=PRT all over 100
435=800(R) (5)all over 100
43500=4000R
:R=10.88%
Answer:
4cos4x
Step-by-step explanation:
let's use cos
amplitude=4
period=pi/2
2pi/x=pi/2
x=4
no phase shift
y=4cos4x
pic from desmos