All categories

3 years ago

How do I solve this?

Mathematics

1 answer:

sasho [114]3 years ago

4 0

Answer:

-m^4n^4

--------------

108

Step-by-step explanation:

You might be interested in

How do i find the missing measurement?

lisabon 2012 [21]

What do u mean by missing measurement?

7 0

3 years ago

In which quadrant is the number –14 – 5i located on the complex plane?

loris [4]

Answer:

The complex number $r = -14 - i\,5$ belongs to the third quadrant of the complex plane.

Step-by-step explanation:

Let be $r = -14 - i\,5$ . In the complex plane, if $\Re (r) < 0$ (real component) and $\Im (r) < 0$ (imaginary component), the number belongs to the third quadrant of the complex plane. The complex number $r = -14 - i\,5$ belongs to the third quadrant of the complex plane.

5 0

2 years ago

A tree casts a shadow 8 meters long. At the same time, a building 64 meters tall casts a shadow 16 meters long. To the nearest m

IceJOKER [234]

Answer:

32 meters

Step-by-step explanation:

If the trees shadow is half the height of the buildings shadow, then the tree is half the size of the building

6 0

2 years ago

Read 2 more answers

Use your shapes to create a new shape with an area of 1 square unit that is not a square. Trace your shape.

Elena-2011 [213]

A new shape with an area of 1 square unit that is not a square can be formed by combining two small triangles

<h3>How to determine the new shape?</h3>

The given parameters are:

Area of square = 1 square unit
Large triangles = 2
Medium triangles = 1
Small triangles = 4

The area of each small triangle is:

Area = 0.5 square unit

Multiply both sides by 2

2 * Area of triangle = 1 square unit

Substitute Area of square = 1 square unit

2 * Area of triangle = Area of square

This means that a new shape can be formed by combining two small triangles

Read more about area at:

brainly.com/question/24487155

#SPJ1

7 0

2 years ago

Finding the inverse of the function x^3+3x+1 is beyond the scope of this course. Nevertheless, you should be able to use your kn

slega [8]

Step-by-step explanation:

${x}^{3} + 3x + 1 = 1 = = = > \\ {x}^{3} + 3x = 0 = = = > \\ x({x}^{2} + 3) = 0 \\ x = 0 \: or \\ {x}^{2} + 3 = 0 = = = > \\ {x}^{2} = - 3 = = = > x 1= \sqrt{ - 3} \: or \: i \sqrt{3} \\ x2 = - \sqrt{ - 3} = = = > x2 = - i \sqrt{3}$

${x}^{3} + 3x + 1 = 5 = = = > \\ {x}^{3} + 3x - 4 = = = > \\ (x - 1)( {x}^{2} + x + 4) = 0 = = = > \\ x - 1 = 0 = = > x1 = 1 \\ {x}^{2} + x + 4 = 0 = = = > \\ x2 = - 1 + i \sqrt{3} \\ x3 = - 1 - i \sqrt{3}$

${x}^{3} + 3x + 1 = 3 = = = > \\{ x}^{3} + 3x - 2 = 0 = = = > x = 0.6$

4 0

1 year ago