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dimulka [17.4K]

2 years ago

9

I will give brainiest to whoever answers correctly !!

1 answer:

Karo-lina-s [1.5K]2 years ago

7 0

Answer:

Step-by-step explanation:

a) The interest generated over the 9 months is how much the woman paid for use of the money, then:

$I=C.t.i\\C=3000\\t=9\\i=3.5%=0.035\\I=3000.9.0.035=945\\I=945$

Therefore , the woman paid $945 for the use of the money.

b) The total amount that she repaid the bank is:

$C_{t} =C+I=3000+945=3945\\C_{t} =3945$

Finally we have that the woman paid $3945 to the bank

PLEASE MARK ME AS BRAINLIEST

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There are 600 students in a school. The ratio of boys to girls is 3:5. How many boys and how many girls are there?

vitfil [10]

Add both amounts together but both multiplied by an unknown value, x.
3x+5x=600
8x=600
8x/8=600/8
x=75
3(75)=225
225 boys
5(75)=375
375 girls

225 boys and 375 girls

8 0

2 years ago

Consider a binomial experiment with 15 trials and probability 0.35 of success on a single trial.

DedPeter [7]

Answer:

a

$P(X = 10 ) = 0.0096$

b

$P(X = 10 ) = 0.0085$

c

Option A is correct

Step-by-step explanation:

From the question we are told that

The sample size is n = 15

The probability of success is $p = 0.35$

The number of success we are considering is r = 10

Now the probability of failure is mathematically evaluated as

$q = 1- p$

substituting value

$q = 1- 0.35$

$q = 0.65$

Now using the binomial distribution to find the probability of exactly 10 successes we have that

$P(X = r ) = [\left n } \atop {r}} \right. ] * p^r * q^{n- r}$

substituting values

$P(X = 10 ) = [\left 15 } \atop {10}} \right. ] * p^{10}* q^{15- 10}$

Where $[\left 15 } \atop {10}} \right. ]$ mean 15 combination 10 which is evaluated with a calculator to obtain

$[\left 15 } \atop {10}} \right. ] = 3003$

So

$P(X = 10 ) = 3003 * 0.35 ^{10}* 0.65^{15- 10}$

$P(X = 10 ) = 0.0096$

Now using the normal distribution to approximate the probability of exactly 10 successes, we have that

$P(X = r ) = P( r < X < r )$

Applying continuity correction

$P(X = r ) = P( r -0.5 < X < r +0.5)$

substituting values

$P(X = 10) = P( 10-0.5 < X < 10+0.5)$

$P(X = 10 ) = P( 9.5 < X < 10.5)$

Standardizing

$P(X = r ) = P( \frac{9.5 - \mu }{\sigma } < \frac{X - \mu }{\sigma } < \frac{10.5 - \mu}{\sigma } )$

The where $\mu$ is the mean which is mathematically represented as

$\mu = n * p$

substituting values

$\mu = 15 * 0.35$

$\mu = 5.25$

The standard deviation is evaluated as

$\sigma = \sqrt{n * p * q }$

substituting values

$\sigma = \sqrt{15 * 0.35 * 0.65 }$

$\sigma = 1.8473$

Thus

$P(X = 10 ) = P( \frac{9.5 - 5.25 }{1.8473 } < \frac{X - 5.25 }{1.8473 } < \frac{10.5 - 5.25}{1.8473 } )$

$P(X = 10 ) = P( 2.30 < Z < 2.842 )$

$P(X = 10 ) = P(Z < 2.842 ) - P(Z < 2.30 )$

From the normal distribution table we obtain the $P(Z < 2.841)$ as

$P(Z < 2.841) = 0.99775$

And the $P(Z < 2.30)$

$P(Z < 2.30) = 0.98928$

There value can also be obtained from a probability of z calculator at (Calculator dot net website)

So

$P(X = 10) = 0.99775 - 0.98928$

$P(X = 10 ) = 0.0085$

Looking at the calculated values for question a and b we see that the values are fairly different.

8 0

3 years ago

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Orlov [11]

I think you do 550 x .16(16%)=88 and each CD sells for 44 so 88/44

Answer= He needs to sell 2 CD's

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3 years ago

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