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ira [324]
4 years ago
7

Which expression is equivalent to (4(5^3)1/2?

Mathematics
1 answer:
Feliz [49]4 years ago
6 0

Answer:

10\sqrt{5}

Step-by-step explanation:

In this problem, we are given expression in exponent form and we have to simplify the expression.

The expression is [4(5^{3} )]^{\frac{1}{2} }

Now, we know that 5^{3} = 5 \times 5 \times 5 = 125

So, 4(5^{3} ) = 4 \times 125 = 500

Now, 500 can be written as 100 × 5 = 10² × 5

Therefore, [4(5^{3} )]^{\frac{1}{2} } = (500)^{\frac{1}{2} } = 10\sqrt{5} {Since 500 = 100 × 5 = 10² × 5} (Answer)

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Problem Sathish is going on a 210021002100-kilometer road trip with 222 friends, whom he will pick up 150150150 kilometers after
Novay_Z [31]

Complete question :

Sathish is going on a 2100-kilometer road trip with 2 friends, whom he will pick up 150 kilometers after he begins the trip and drop off when there are 150 kilometer remaining. The car consumes 6 liters of gas for every 100 kilometers, and gas costs $1.20 per liter.

Sathish will pay for all of the gas when he is alone in the car, but he and his friends will split the cost evenly when they are together.

How much will Sathish pay for gas?

Answer:

$64.8

Step-by-step explanation:

Given that :

Total length of trip = 2100 km

Length of journey with Satish alone in the car:

(150km) beginning + (150km) ending = 300km

Length of journey with Satish and 2 friends :

2100 km - 300 km = 1800 km

Gas consumption:

6 liters per 100km

Cost of gas = $1.2 / litre

Consumption when Satish is alone :

(6 litres /100 km) * 300km = 18 litres

Cost = $1.2 * 18 = $21.6

Consumption with his 2 friends :

(6 litres /100 km) * 1800 km = 10800 / 100 = 108 litres

Cost = $1.2 * 108 = $129.6

Since amount is shared equally :

Amount paid by sattish = $129.6 / 3 = $43.2

Hence, total amount paid by Sattish is :

$21.6 + $43.2

= $64.8

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Answer:

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Step-by-step explanation:

14/2 + 5 * 4

Order of operations:

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If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

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Help plz I need this answer
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