which graph represents a line with a slope of -2/3 and a yintercept equal to that of the line y=2/3x-2

What is the slope of (-3,2) and (6,1)

evablogger [386]

Answer: -1/9

Step-by-step explanation:

Find the Slope (−3, 2) and (6, 1)

Slope is equal to the change in y over the change in x, or rise over run.

$m=\frac{change in y}{change in x}$

The change in x is equal to the difference in x-coordinates (also called run), and the change in y

is equal to the difference in y-coordinates (also called rise).

$m = \frac{y_2-y_1}{x_2-x_1}$

Substitute in the values of x and y into the equation to find the slope.

$m = \frac{1-(2)}{6-(-3)}$

Simplify the numerator. Tap for more steps...

$m=\frac{-1}{6-(-3)}$

Simplify the denominator.

$m=-\frac{1}{9}$

6 0

2 years ago

Read 2 more answers

10 PIONTS+BRAINLYESS

nikdorinn [45]

Plantation owners wabted runaways slaves

8 0

2 years ago

A trapezoid has an area of 266.4 square feet. One base is 8.5 feet long. The height measures 24 feet. What is the length of the

exis [7]

266.4 - 8.5 - 24 will give you the answer of 233.9

6 0

3 years ago

i have 6 digits. One of my 3s is worth 300.000. The other is worth 1/10 as much. My 6 is worth 600.The rest of my digits are zer

motikmotik

The way you wrote the problem makes the answer 330,600. I think your decimals were meant to be commas. If I am wrong, please forgive me.

3 0

3 years ago

Express the system as AX = B; then solve using matrix inverses

Wittaler [7]

Answer with explanation:

1. The given equations are

3x -5 y=2

-x+2 y= 0

⇒The matrix in the form of , AX=B, is

$A=\left[\begin{array}{cc}3&-5\\-1&2\end{array}\right] ,\\\\ X=\left[\begin{array}{c}x&y\end{array}\right],\\\\B=\left[\begin{array}{c}2&0\end{array}\right]$

$\rightarrow X=A^{-1}B\\\\\rightarrow X=\frac{Adj.A}{|A|}\times B$

Adj.A=Transpose of cofactor of Matrix A

$Adj.A=\left[\begin{array}{cc}2&1\\5&3\end{array}\right] ,\\\\ |A|=6-5\\\\|A|=1\\\\\left[\begin{array}{c}x&y\end{array}\right]=\left[\begin{array}{cc}2&5\\1&3\end{array}\right] \times \left[\begin{array}{c}2&0\end{array}\right]\\\\x=4, y=2$

2.

The given equations are

x+y-z=2

x+z=7

2 x +y+z=13

⇒The matrix in the form of , AX=B, is

$A=\left[\begin{array}{ccc}1&1&-1\\1&0&1\\2&1&1\end{array}\right]\\\\ X=\left[\begin{array}{ccc}x\\y\\z\end{array}\right]\\\\B= \left[\begin{array}{ccc}2\\7\\13\end{array}\right]\\\\\rightarrow X=A^{-1}B\\\\\rightarrow X=\frac{Adj.A}{|A|}\times B\\\\a_{11}=-1,a_{12}=1,a_{13}=1,a_{21}=-2,a_{22}=3,a_{23}=1,a_{31}=1,a_{32}=-2,a_{33}=-1\\\\|A|=1\times(0-1)-1\times(1-2)-1\times(1-0)\\\\=-1+1-1\\\\|A|=-1\\\\Adj.A=\left[\begin{array}{ccc}-1&-2&1\\1&3&-2\\1&1&-1\end{array}\right]$

$\frac{Adj.A}{|A|}=\left[\begin{array}{ccc}1&2&-1\\-1&-3&2\\-1&-1&1\end{array}\right]\\\\X=A^{-1}B\\\\\left[\begin{array}{ccc}x\\y\\z\end{array}\right]=\left[\begin{array}{ccc}1&2&-1\\-1&-3&2\\-1&-1&1\end{array}\right]\times\left[\begin{array}{ccc}2\\7\\13\end{array}\right]\\\\x=3,y=3,z=4$

7 0

3 years ago