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Andrej [43]
3 years ago
8

Find the measure of angle 1. 152 115 mZ1 = Please help mee:(

Mathematics
1 answer:
Elis [28]3 years ago
6 0

Answer:

37°

Step-by-step explanation:

We have been given the diagram of the triangle;

 To find the angle I;

 We need to apply one of the geometry laws,

The sum of adjacent internal angles of a triangle gives the external angle;

So;

      I + 115  = 152

   Solve for I;

      I  = 152 - 115 = 37°

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A.48<br> B.54<br> C.102<br> D.105
Mars2501 [29]

Answer:

D

Step-by-step explanation:

i did this one

8 0
3 years ago
FIND THE EXACT AREA PLEASE HELPPPP ILL GIVE BRAINLIESTTTT
Ede4ka [16]

Answer:

555.94

Step-by-step explanation:

16 x 11 = 176/2

88

since there are two of the same triangle

88 x 2

176

11 is the radius

A = \pix^{2}

A = 3.14 ( pie is 3.14, if not then pi) x (11x11)

A = 3.14 x 121 (or 121\pi)

A = 379.94

379.94 + 176 (or 121pi + 176)

555.94

4 0
2 years ago
Helppppp pls will put brainliest
mojhsa [17]

Answer:jai can bake 42 cakes in a week

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP!!!!!!!! I ONLY HAVE 20 MORE MINUTES AND I HAVE LIKE EIGHT MORE QUESTIONS!!!
sertanlavr [38]

Answer:

I'm pretty sure its -4-12x but I could be wrong

Step-by-step explanation:

First I tried to solve for x but got -12x+4 so to get 4 on the other side of the equation I subtracted and got -4-12x I hope this helps :)

7 0
3 years ago
Help solve 4 and 5 please
Sloan [31]

Answer:

Step-by-step explanation:

4). a). If the diagonals of a parallelogram are congruent, then it must be a RECTANGLE.

b). If the diagonals of a parallelogram are perpendicular, then it must be a SQUARE.

c). If the diagonals of a parallelogram bisect the angles of the parallelogram, then it must be a RHOMBUS.

d). If the diagonals of a parallelogram are perpendicular and congruent, then it must be a SQUARE.

e). If a parallelogram has four congruent sides, then it must be a SQUARE.

5). Given quadrilateral SELF is a rhombus.

a). All sides of a rhombus are equal,

   Therefore, ES = EL = 25

b). Diagonals of a rhombus bisects the opposite angles,

   Therefore, m∠ELS = m∠FLS

    3x - 2 = 2x + 7

    3x - 2x = 7 + 2

    x = 9

c). Diagonals of the rhombus bisect the opposite angles, and adjacent angles are supplementary.

m∠ELF = 2(m∠ELS) = 2(2y - 9)

m∠LES = 2(m∠LEF) = 2(3y + 9)

And 2(2y - 9) + 2(3y + 9) = 180

(2y - 9) + (3y + 9) = 90

5y = 90

y = 18  

6 0
3 years ago
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