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4 years ago

12 out of 20 doctors agree 15 out of 30 doctors agree are the ratios equivalent

Mathematics

1 answer:

uysha [10]4 years ago

4 0

No it is not because 15 out of 30 is half but 12 out of 20 is more than half

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Is 16 lb greater than 256 oz?

Black_prince [1.1K]

Since there are 16 oz in 1 lb, take 256, divide it by 16, and the answer is 16. Therefore both are the same because 16 lbs = 16lbs

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3 years ago

Read 2 more answers

What is the simplest form for 13/8

Crank

Its already in simplest form but you can convert it to a mixed fraction and get:
1 5/8

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3 years ago

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A set has 62 proper subsets how many elements has it for?<br>

MrRissso [65]

Answer:

Step-by-step explanation:

Total number of subsets is given as

${2}^{n}$

But the subset of a set consists of the proper subsets, an empty set and the set itself.

Total number of subsets are 64

Therefore,

${2}^{n} = 64$

${2}^{n} = {2}^{6}$

Comparing both sides

$n = 6$

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3 years ago

A recipe that makes 7 servings calls for 1 1/6 cups of juice.

VMariaS [17]

1/7 cups per serving

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3 years ago

In selecting a sulfur concrete for roadway construction in regions that experience heavy frost, it is important that the chosen

Lesechka [4]

Step-by-step explanation:

Given - In selecting a sulfur concrete for roadway construction in regions that experience heavy frost, it is important that the chosen concrete has a low value of thermal conductivity in order to minimize subsequent damage due to changing temperatures. Suppose two types of concrete, a graded aggregate and a no-fines aggregate, are being considered for a certain road. The table below summarizes data on thermal conductivity from an experiment carried out to compare the two types of concrete.

Type ni xi si

Graded 42 0.486 0.187

No-fines 42 0.359 0.158

To find - a. Formulate the above in terms of a hypothesis testing problem.

b. Give the test statistic and its reference distribution (under the null hypothesis).

c. Report the p-value of the test statistic and use it to assess the evidence that this sample provides on the scientific question of difference in mean conductivity of the two materials at the 5% level of significance.

Proof -

a.)

Hypothesis testing problem :

H0 : There is significant difference between mean conductivity for the graded concrete and mean conductivity for the no fines concrete.

H1 : There is no significant difference between mean conductivity for the graded concrete and mean conductivity for the no fines concrete.

Test statistic :

$Z = \frac{x_{1} - x_{2} }{\sqrt{\frac{s_{1} ^{2} }{n_{1}} + \frac{s_{2}^{2} }{n_{2}} } }$

$Z = \frac{0.486 - 0.359 }{\sqrt{\frac{0.03496 }{42} + \frac{0.02496 }{42} } }$

$Z = \frac{0.127 }{\sqrt{0.001468}}$

$Z = \frac{0.127 }{0.0377}$

⇒Z(cal) = 3.3687

Z(tab) = 1.96

As Z (cal) > Z(tab)

So, we reject H0 at 5% Level of significance

p-value = 0.99962

Hence

There is significant difference in mean conductivity at the two materials.

5 0

3 years ago