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3 years ago

What is the least common multiple of 12 and 18?

Mathematics

2 answers:

N76 [4]3 years ago

8 0

2. the answer is 2because both numbers are even

Contact [7]3 years ago

6 0

Answer: 36

Step-by-step explanation: A common multiple is a number that is a multiple of at least two numbers.

To find out the least common multiple of 12 and 18, we can use prime factorization for each number.

12 = 2 × 2 × 3

18 = 2 × 3 × 3

Least Common Multiple = 2 × 2 × 3 × 3 = 36

LCM of 12 and 18 is 36.

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umka2103 [35]

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x = 10°

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3 years ago

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3 years ago

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3 years ago

Assume you have such a watch. if a minimum of 18.0% of the original tritium is needed to read the dial in dark places, for how m

laila [671]

Given that the half life of 3H is 12.3 years.

The amount of substance left of a radioactive substance with half life of $t_{ \frac{1}{2} }$ after t years is given by

$N(t)=N_0\left(\frac{1}{2} \right)^{ \frac{t}{t_{\frac{1}{2}} }$

Therefore, the number of years it will take for 18% of the original tritinum to remain is given by

$18 \% = 100 \% \left(\frac{1}{2} \right)^{ \frac{t}{12.3}} \\ \\ \Rightarrow\left(\frac{1}{2} \right)^{ \frac{t}{12.3}} =0.18 \\ \\ \Rightarrow\frac{t}{12.3}\ln\left(\frac{1}{2} \right)=\ln0.18 \\ \\ \Rightarrow\frac{t}{12.3}= \frac{\ln0.18}{\ln\left(\frac{1}{2} \right)} = \frac{-1.715}{-0.6931} =2.474\\ \\ \Rightarrow t=2.474(12.3)=30.4$

Therefore, the number of <span>years that the time could be read at night is 30.4 years.</span>

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3 years ago

Suppose we are given the following.

Mashutka [201]

Answer:

Slope of line 1 = 3

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Slope of line 3 = -1/3

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Line 1 and 3 = perpendicular

Line 2 and 3 = perpendicular

Step-by-step explanation:

trust me its correct

pls mark me as brainliest

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3 years ago