On Monday, 279 students went on a trip

Help on this one as well ii manged to get an answer but If you understand it or im wrong an you please explain ! thank you !!

AnnZ [28]

Almost got it!

x + 3 = 3(y + 2)/2 [Multiplied both sides by 3]
so x + 3 = (3y + 6)/2
2(x + 3) = 3y + 6 [Multiplied both sides by 2]
2x + 6 = 3y + 6
2x = 3y [Subtracted 6 from both sides]
x = 3y/2 [Divided both sides by 2]
x/3 = y/2 [Divided both sides by 3]

So you wrote y/3 instead of y/2
Hope this helped!

8 0

3 years ago

Read 2 more answers

The quadratic function in vertex form of a parabola vertex 1,1 and passes through 4,19

Grace [21]

Answer:

y = 2(x - 1)² + 1

Step-by-step explanation:

The equation of a quadratic function in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Here (h, k) = (1, 1), thus

y = a(x - 1)² + 1

To find a substitute (4, 19) into the equation

19 = a(4 - 1)² + 1

19 = 9a + 1 ( subtract 1 from both sides )

18 = 9a ( divide both sides by 9 ), thus

a = 2

y = 2(x - 1)² + 1 ← in vertex form

5 0

3 years ago

Alfred is building a slide for a new park. He wants the height of the slide to be 8 feet, and he wants the horizontal distance a

oksano4ka [1.4K]

Answer:

5ft

Step-by-step explanation:

8/10=0.8

4/0.8=5

8 0

2 years ago

Median? 93; 17; 85; 42; 15; 19; 78

love history [14]

The median is the number in the middle when all of the numbers are placed in order (from lowest to highest).

15; 17; 19; 42; 78; 85; 93

The answer in this case would be 42.

6 0

3 years ago

There are two games involving flipping a coin. In the first game you win a prize if you can throw between 45% and 55% heads. In

Nina [5.8K]

Answer:

d) 300 times for the first game and 30 times for the second

Step-by-step explanation:

We start by noting that the coin is fair and the flip of a coin has a probability of 0.5 of getting heads.

As the coin is flipped more than one time and calculated the proportion, we have to use the <em>sampling distribution of the sampling proportions</em>.

The mean and standard deviation of this sampling distribution is:

$\mu_p=p\\\\ \sigma_p=\sqrt{\dfrac{p(1-p)}{N}}$

We will perform an analyisis for the first game, where we win the game if the proportion is between 45% and 55%.

The probability of getting a proportion within this interval can be calculated as:

$P(0.45$

referring the z values to the z-score of the standard normal distirbution.

We can calculate this values of z as:

$z_H=\dfrac{p_H-\mu_p}{\sigma_p}=\dfrac{(p_H-p)}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p_H-p)>0\\\\\\z_L=\dfrac{p_L-\mu_p}{\sigma_p}=\dfrac{p_L-p}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p_L-p)$

If we take into account the z values, we notice that the interval increases with the number of trials, and so does the probability of getting a value within this interval.

With this information, our chances of winning increase with the number of trials. We prefer for this game the option of 300 games.

For the second game, we win if we get a proportion over 80%.

The probability of winning is:

$P(p>0.8)=P(z>z^*)$

The z value is calculated as before:

$z^*=\dfrac{p^*-\mu_p}{\sigma_p}=\dfrac{p^*-p}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p^*-p)>0$

As (p*-p)=0.8-0.5=0.3>0, the value z* increase with the number of trials (N).

If our chances of winnings depend on P(z>z*), they become lower as z* increases.

Then, we can conclude that our chances of winning decrease with the increase of the number of trials.

We prefer the option of 30 trials for this game.

8 0

3 years ago