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sashaice [31]
3 years ago
5

Choose the fraction that is equal to: 0.63 A 7/9 B 7/11 C 2/3 D 63/100

Mathematics
2 answers:
Fudgin [204]3 years ago
7 0

Answer:

Step-by-step explanation:

It would be D.

Murljashka [212]3 years ago
3 0
The answer is D

Hope I helped!!
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USA test prep please answer
sergij07 [2.7K]

Answer:

D

Step-by-step explanation:

8 0
2 years ago
What is the product of 2•2
lisabon 2012 [21]

Answer:

4

Step-by-step explanation:

2*2 can be modeled using the following.

2 rows of 2

| |

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Total 4 sticks

7 0
2 years ago
on a map with a scale 1: 25000,the area of a lake is 33.6 square centimeters. calculate the actual area of the lake, giving your
svlad2 [7]

Given :

On a map with a scale 1: 25000 .

The area of a lake is 33.6 square centimeters.

To Find :

The actual area of the lake.

Solution :

Let, actual area of lake is A.

So,

\dfrac{33.6}{A}=\dfrac{1}{25000}\\\\A = 840000\ cm^2

We know , 1 \ cm^2 = 10^{-10}\ km^2

Area in km² is :

A = 840000\times 10^{-10}\ km^2\\\\A = 8.4 \times 10^{-5}\ km^2

Hence, this is the required solution.

6 0
2 years ago
A manufacturing facility produces rolls of tape. Among all of the rolls of tape produced, the mean length of the tape on a roll
Anna [14]

Answer:

P(\bar X< 651.1) =P(\bar X< \frac{651.1-651.25}{\frac{0.73}{\sqrt{78}}}= -1.815

And using the normal atandard table or excel we got:

P(z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

Let X the random variable that represent the length of the tape of a population, and for this case we know the following parameters

Where \mu=651.25 and \sigma=0.73

We sselect a sample size of n =78>30. From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we want to find this probability:

P(\bar X< 651.1) =P(\bar X< \frac{651.1-651.25}{\frac{0.73}{\sqrt{78}}}= -1.815

And using the normal atandard table or excel we got:

P(z

8 0
3 years ago
Help me asap.........
sattari [20]

Answer:

  F.  4h ≥ 18

Step-by-step explanation:

Liang wants ...

   distance ≥ goal

We know that ...

   distance = speed · time . . . . . . where speed = 4 mph, and time = h hours

Then the appropriate inequality for Liang's goal of 18 miles or more is ...

  4h ≥ 18

7 0
3 years ago
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