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Nastasia [14]
3 years ago
15

Find the area of the circle. Round your answer to the nearest hundredth. 00 3 in.

Mathematics
1 answer:
MAXImum [283]3 years ago
4 0

Answer:

Step-by-step explanation:300

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Box A contains 1 black and 3 white marbles, and box B contains 2 black and 4 white marbles. A box is selected at random, then a
Anna11 [10]

Answer: Probability that Box A was chosen given that black marble is chosen is 0.5.

Step-by-step explanation:

Since we have given that

Number of boxes = 2

In Box A,

Number of black marbles = 1

Number of white marbles = 3

In Box B,

Number of black marbles = 2

Number of white marbles = 4

Since black marble is selected.

So, using Bayes theorem , we get that

P(E_1|B)}=\dfrac{P(E_1).P(B|E_1)}{P(E_1).P(B|E_1)+P(E_2).P(E_2|B)}\\\\P(E_1|B)=\dfrac{0.5\times \dfrac{1}{3}}{0.5\dfrac{1}{3}+0.5\times \dfrac{2}{6}}\\\\P(E_1|B)}=\dfrac{0.167}{0.167+0.167}\\\\P(E_1|B)}=0.5

Hence, probability that Box A was chosen given that black marble is chosen is 0.5.

3 0
2 years ago
if the rate of change of a population is given by dP/dt=3.1(P-2)(P-10), P>0, for what values of P is the population increasin
Gemiola [76]
You have to test dp/dt between these intervals
(-inf,2)
(2,10)
(10,inf)
if dp/dt is positive then the population is increasing with respect to time in that interval
6 0
3 years ago
I need answer on this problem tyt​
tamaranim1 [39]
<h3>Speed of light:</h3>

3.05 \times 10 ^{8} m/s

<h3 /><h3>Seconds in a year:</h3>

3.15 \times 10 ^{7}

\rule{300pt}{3pt}

Multiply the speed of light with seconds in a year

*Note:- We will not change the values because speed of light is in m/s and the time is also given in seconds.

\rule{300pt}{3pt}

3.08 \times 10 ^{8}  \times 3.15 \times 10 ^{7}

(3.05 \times 3.15) \times (10 ^{8}  \times 10 ^{7} )

9.4675 \times 10 ^{15}

\tt9.46 \: Trillion \: Kilometers

3 0
2 years ago
Two functions are given.
ArbitrLikvidat [17]

Hi

f(x) = g(x)   if    -x²+3x-2   - ( -x+1) = 0

                      -x² +3x-2 +x-1 = 0

                      -x² +4x -3 = 0

To solve, tou have to use the general method of resolution of a quadratic fonction.  

To determine if it's has a solution in R, let's calculate  Δ

Δ = (4)² - 4 * (1) *(-3)

Δ = 16 +12

Δ= 28  

as Δ≥ 0  so  the function allow two solution within R  

so S 1 =  ( -4 +√28) / 2            S 2 =   (-4 -√28 ) /2

    S1 =   ( -4 + 2√7) /2            S2 =    (-4 - 2√7) /2

    S1 =    (2 (-2 +√7) /2            S2      2 (-2 -√7)   /2

    S1 =    -2 +√7                       S2 =      -2 -√7

So the two function  are equal   twice. one  for   x = -2 +√7  and second x = -2-√7

4 0
3 years ago
Is 60n + 12 equal to 12(5n + 1)
hram777 [196]

Answer: no

Step-by-step explanation:

5 0
3 years ago
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