Answer:
0.1505 = 15.05% probability that the hockey team wins 6 games in November
Step-by-step explanation:
For each game, there are only two possible outcomes. Either the team wins, or it does not. The probability of winning a game is independent of winning other games. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which 
is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
The probability that a certain hockey team will win any given game is 0.3723
So 
12 games in November
So 
What is the probability that the hockey team wins 6 games in November?
This is 
0.1505 = 15.05% probability that the hockey team wins 6 games in November
Answer:
No
Step-by-step explanation:
Answer:
43,000: 4.3×10^4
0.0072: 7.2×10^-3
0.0000901: 9.01×10^-5
Step-by-step explanation:
scientific notation: a×10^b, where should be 0<a<10
Step 1. Count the zeros
Step 2. Look at the number left, and determine whether or not it fits in the range of [a]. If not, we divide or multiply 10 to get it fit
------------------------
43,000: 4.3×10^4 (since 43 does not fit, we divide by 10 to get it fit)
0.0072: 7.2×10^-3 (since 0.72 does not fit, we multiply 10 to get it fit)
0.0000901: 9.01×10^-5 (since 0.901 does not fit, we multiply 10 to get it fit)
Hope this helps!! :)
Please let me know if you have any question
the yearly increase of x% assumes is compounding yearly, so let's use that.
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