A hiker walks up and down a hill. The hill’s cross section can be modeled by the function y = – 3/4|x – 300| + 400 where x and y
are measured in feet and D: [0, 600]. How far does the hiker walk?
1 answer:
You might be interested in
Answer:
A) y = 3(x -3)^2 -46
B) (3, -46)
C) look at the y-coordinate of the vertex
Step-by-step explanation:
A) Factor the leading coefficient from the variable terms.
y = 3(x^2 -6x) -19
Inside parentheses, add the square of half the x-coefficient. Outside, subtract the same value.
y = 3(x^2 -6x +9) -19 -3(9)
y = 3(x -3)^2 -46
__
B) Compared to the vertex form, ...
y = a(x -h)^2 +k
we find a=3, (h, k) = (3, -46).
The vertex is (3, -46).
__
C) The vertex is an extreme value (as is any vertex). The sign of the leading coefficient tells you whether the parabola opens upward (+) or downward (-). This parabola opens upward, so the vertex is a minimum.
If the leading coefficient is positive, the y-coordinate of the vertex is a minimum. If the leading coefficient is negative, the y-coordinate of the vertex is a maximum.
Answer: There are 980 degrees of freedom for the within subjects factor.
Step-by-step explanation:
Since we have given that
Number of groups = 20
Number of participants in each group = 50
So, number of participants in 20 groups is given by
As we know that
Degrees of freedom for the within subjects factor would be
Hence, there are 980 degrees of freedom for the within subjects factor.