Answer: the statements and resons, from the given bench, that fill in the blank are shown in italic and bold in this table:
Statement Reason
1. K is the midpoint of segment JL Given
2. segment JK ≅ segment KL <em>Definition of midpoint</em>
3. <em>L is the midpoint of segment KM</em> Given
4. <em>segment KL ≅ segment LM</em> Definition of midpoint
5. segment JK ≅ segment LM Transitive Property of
Congruence
Explanation:
1. First blank: you must indicate the reason of the statement "segment JK ≅ segment KL". Since you it is given that K is the midpoint of segment JL, the statement follows from the very <em>Definition of midpoint</em>.
2. Second blank: you must add a given statement. The other given statement is <em>segment KL ≅ segment LM</em> .
3. Third blank: you must indicate the statement that corresponds to the definition of midpoint. That is <em>segment KL ≅ segment LM</em> .
4. Fourth and fith blanks: you must indicate the statement and reason necessary to conclude with the proof. Since, you have already proved that segment JK ≅ segment KL and segment KL ≅ segment LM it is by the transitive property of congruence that segment JK ≅ segment LM.
Answer:
Step-by-step explanation:
The goal is to construct a triangle. If you choose A) you will only have two lines connecting, with an angle of 90°. If you choose B) you cannot have a triangle also with 2 lines only. Neither D). So choose C) construct an angle congruent to a given one-- connect the lines and produce a perfect triangle.
Given :
A right angle triangle ABC .
To Find :
The perimeter of ABC .
Solution :
Since, triangle ABC is right angled and angle ∠ABC is 46° .
So, AC = AB cos 46° = 7.64 units.
Also, CB = AB sin 46° = 7.91 units.
Therefore, the perimeter of ΔABC is :
P = 11 + 7.64 + 7.91 units
P = 26.55 units
Hence, this is the required solution.
