Answer:
-8x^2+6x-20
Step-by-step explanation:
2(x^2+3x)-10(x^2+2)
2x^2+6x-10x^2-20
(2x^2-10x^2)+6x-20
-8x^2+6x-20
Let after n week both tanks have same quantity of water .
for first tank
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tank hold 540 gallon of water ,
leaking of water 4 gallon /week
so, in n week water leak from the tank =4× n = 4n
now, after n week quantity of water in the tank = 540 -4n
for second tank
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quantity of water in the tank =720 gallon
leaking of water at the rate = 7gallon/week
so, after n week water leak from the tank = 7× n =7n
after n week quantity of water rest in the tank = 720 -7n
now ,
according to question ,
water in first tank = water in second tank
540 -4n = 720 -7n
7n -4n = 720 -540
3n = 180
n = 60
hence , after 60 week both tank have same quantity of water.
1/5 is greater because it equals 0.2
0.2 has an imaginary 0 at the end, to make it 0.20
.20 > 0.15
Therefore, 1/5 is greater than 0.15
What does it constraints?
