Step-by-step explanation:
step 1. what is the question? solve for k? okay.
step 2. 4(k - 6) = 6(-4 - 5k)
step 3. 4k - 24 = -24 - 30k
step 4. 34k = 0
step 5. k = 0.
Answer:
1/3000
Step-by-step explanation:
3 meters to centimeters:
3 × 100 = 300
= 1/10 ÷ 300
= 1/10/300
= 1/(10×300)
= 1/3000
Answer:
a) 
b) 
c) 
Step-by-step explanation:
For total cost function
, average cost is given by
i.e., total cost divided by number of units produced.
Marginal average cost function refers to derivative of the average cost function i.e., 
Given:
Average cost = 
a)
At x = 50 units,

b)
Average cost = 
c)
Marginal average cost:
Differentiate average cost with respect to 
Take 
using quotient rule, 
Therefore,

Answer:
<u>Equation</u>: 
<u>The balance after 5 years is: $1742.43</u>
<u></u>
Step-by-step explanation:
This is a compound growth problem . THe formula is:

Where
F is future amount
P is present amount
r is rate of interest, annually
n is the number of compounding per year
t is the time in years
Given:
P = 1500
r = 0.03
n = 12 (compounded monthly means 12 times a year)
The compound interest formula modelled by the variables is:

Now, we want balance after 5 years, so t = 5, substituting, we get:

<u>The balance after 5 years is: $1742.43</u>
Answer:
(1.7x10^13)+(0.8x10^13)
=(1.7x1e+13)+(0.8x1e+13)
=1.7e+13+0.8e+13
=2.5e+13
in actual number it would be 25,000,000,000,000
Step-by-step explanation: