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3 years ago

Consider a circle with center (2, −3) that passes through the point (5, 4).

Mathematics

1 answer:

AleksandrR [38]3 years ago

7 0

2,2 and 4.5 would be a circle in this point

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Use the Taylor series you just found for sinc(x) to find the Taylor series for f(x) = (integral from 0 to x) of sinc(t)dt based

Marina CMI [18]

In this question (brainly.com/question/12792658) I derived the Taylor series for $\mathrm{sinc}\,x$ about $x=0$ :

$\mathrm{sinc}\,x=\displaystyle\sum_{n=0}^\infty\frac{(-1)^nx^{2n}}{(2n+1)!}$

Then the Taylor series for

$f(x)=\displaystyle\int_0^x\mathrm{sinc}\,t\,\mathrm dt$

is obtained by integrating the series above:

$f(x)=\displaystyle\int\sum_{n=0}^\infty\frac{(-1)^nx^{2n}}{(2n+1)!}\,\mathrm dx=C+\sum_{n=0}^\infty\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}$

We have $f(0)=0$ , so $C=0$ and so

$f(x)=\displaystyle\sum_{n=0}^\infty\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}$

which converges by the ratio test if the following limit is less than 1:

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(-1)^{n+1}x^{2n+3}}{(2n+3)^2(2n+2)!}}{\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}}\right|=|x^2|\lim_{n\to\infty}\frac{(2n+1)^2(2n)!}{(2n+3)^2(2n+2)!}$

Like in the linked problem, the limit is 0 so the series for $f(x)$ converges everywhere.

7 0

3 years ago

Help me please!!! I will give Brainly if correct!

Alexxandr [17]

Answer:

B, 20mph

Step-by-step explanation:

540 miles in 27 hours is 540/27 = 20 miles in 1 hour. This is 20 mph

3 0

2 years ago

Read 2 more answers

What is the hypothesis of a triangle with a base of 11cm and height of 9cm

natima [27]

<u>Answer:</u>

<u>Explanation:</u>

you mean the hypotenuse* lol

the hypotenuse = √(11²+9²)

the hypotenuse = √(121+81)

the hypotenuse = √(202)

the hypotenuse ≈ 14.21 cm

3 0

2 years ago

Explain the properties of exponents with examples of your own

11Alexandr11 [23.1K]

This is an example of the quotient of powers property and tells us that when you divide powers with the same base you just have to subtract the exponents. When you raise a quotient to a power you raise both the numerator and the denominator to the power. When you raise a number to a zero power you'll always get 1.

3 0

3 years ago

How do you solve for 5/6w = 2/3 (the answer is w= 4/5) I just don’t know how to show it.

Readme [11.4K]

Answer:

5/6w=2/3

5/6(4/5)=2/3

20/30=2/3

20/30=10/15=2/3=2/3

Proof:

5/6w=2/3

6/5*5/6w=2/3*6/5

30/30w=2/3*6/5

w=12/15=4/5

Hope this helps ;) ❤❤❤

6 0

3 years ago