Can someone explain how you would find the answer
2 answers:
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Data:
r (radius) = 3.5 in
h (height) = 8 in
Adopt:
V (volume) = ?
Ink cost per cubic inch = $0.05/in³
Total cost: ?
<span>Calculate the volume of the paint bucket (its formed being cylindrical), we have:
</span>
<span>What was the total cost of the paint?
</span>price($)___measure(in³)
0.05 ---------- 1
y -------------- 307.72
It is made the rule of three: (<span>directly proportional)
</span>
multiply cross
Answer:
<span>the total cost of the paint is $15</span>
r (radius) = 3.5 in
h (height) = 8 in
Adopt:
V (volume) = ?
Ink cost per cubic inch = $0.05/in³
Total cost: ?
<span>Calculate the volume of the paint bucket (its formed being cylindrical), we have:
</span>
<span>What was the total cost of the paint?
</span>price($)___measure(in³)
0.05 ---------- 1
y -------------- 307.72
It is made the rule of three: (<span>directly proportional)
</span>
multiply cross
Answer:
<span>the total cost of the paint is $15</span>
Answer:
1) False, to begin converting the equation to standard form, each side must be added by 36. 2) True, to complete the square for the x terms, add 4 to both sides, 3) True, the center of the circle is at (-2, 3), 4) False, the center of the circle is at (-2, 3), 5) False, the radius of the circle is 7 units, 6) False, the radius of the circle is 7 units.
Step-by-step explanation:
Let prove the validity of each choice:
1) To begin converting the equation to standard form, subtract 36 from both sides:
Let consider the following formula and perform the following algebraic operations:
(i) Given
(ii) Commutative Property
(iii) Modulative/Associative Property/Additive Inverse Existence
(iv) Perfect Trinomial Square
(v) Commutative Property/Compatibility with Addition/Additive Inverse Existence/Modulative Property
(vi) Definition of Addition/Result
False, to begin converting the equation to standard form, each side must be added by 36.
2) True, step (iii) on exercise 1) indicates that both side must be added by 4.
3) The general equation for a circle centered at (h, k) is of the form:
Where is the radius of the circle.
By direct comparison, it is evident that circle is centered at (-2,3).
True, step (vi) on exercise 1) indicates that center of the circle is at (-2, 3).
4) False, step (vi) on exercise 1) indicates that the center of the circle is at (-2, 3), not in (4, -6).
5) After comparing both formulas, it is evident that radius of the circle is 7 units.
False, the radius of the circle is 7 units.
6) After comparing both formulas, it is evident that radius of the circle is 7 units.
False, the radius of the circle is 7 units.