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g100num [7]
3 years ago
7

The test scores for a group of students are shown.

Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
5 0

the mode is what occurs the most. 87 occurs once, 72 occurs 3 times, 98 occurs once,84 occurs twice,  65 occurs once, 70 occurs once, 58 occurs once , 91 occurs once and 84 occurs once.  <em><u> 72  </u></em><em><u /></em><u />  occurs 3 times, which is the most, so <em><u> 72  </u></em> is the mode.
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Is 7(x+2y) the equivalent of 14x + 14y
ryzh [129]

Answer:

the expressions are not equivalent

Step-by-step explanation:

7(x+2y)    (distribute 7 into the parentheses)

= x(7) + 2y(7)

= (7x + 14y)  ≠ (14x + 14y)

hence the expressions are not equivalent

8 0
3 years ago
A DVD costs $17.45. What is 6.75% sales tax?
luda_lava [24]

6.75 % x 17.45

= $18.63

6 0
3 years ago
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Is the answer 200? Or 4.5??? Or is none ? I don't know it's confusing :/ can I get help :/
skelet666 [1.2K]
Let x = the number of penguins we are finding

x ÷ 100 × 30 = 15
x = 15 ÷ 30 × 100
x = 50

hope this helps and have a great day :)


6 0
3 years ago
Read 2 more answers
The perimeter of a rectangle is 30.8 km and it’s diagonal length is 11 km. Find it’s length and width
blsea [12.9K]

Answer:

Length of the rectangle is 15.0325 km and width is 0.3765 km.

Explanation:

Given:

Perimeter of a rectangle = 30.8 km

Length of diagonal of rectangle = 11 km

To find:

The length and width of rectangle=?

Solution:

Lets assume length of the rectangle = x km

And assume width of the rectangle = y km

Lets first create equation using given  perimeter

perimeter of rectangle = 2 ( length +  width )

=> 30.8 km = 2 ( x + y )  

=>x + y = \frac{30.8}{2}

=> y = 15.4 – x             ------(1)

As diagonal and two sides of rectangle forms right angle triangle whose hypoteneus is diagonal ,  

=> length^2 + width^2 = diagonal^2

=> x^2 + y^2 = 11^2

=> x^2 + y^2 = 121

On substituting value of y from (1) in above equation we get

=> x^2 + (15.4-x)^2 = 121

=>x^2 + (15.4)^2 + x^2 – 2 x 15.4 \times x   = 121

=> 2x^2-30.8x + 237.16 -121  = 0

=> 2x^2-30.8x + 116.16 = 0

Solving above quadratic equation using quadratic formula

General form of quadratic equation is  

ax^2 +bx +c = 0

And quadratic formula for getting roots of quadratic equation is  

x= \frac{ -b\pm\sqrt{(b^2-4ac)}}{2a}

As equation is 2x^2-30.8x + 116.16 = 0, in our case

a = 2 ,  b = -30.8 and c = 116.16

Calculating roots of the equation we get

x=\frac{ -(-30.8)\pm\sqrt{(-30.8)^2-4(2)( 11)} } {(2\times2)}

x=\frac{30.8\pm\sqrt{(948.64-88)}}{4}

x=\frac{30.8\pm\sqrt{860.64}}{4}

x=\frac{30.8\pm\sqrt{860.64}}{4}

x=\frac{(30.8\pm29.33)}4

x=\frac{(30.8+29.33)}{4}

x=\frac{(30.8-29.33)}{4}

=> x = 15.0325 or x = 0.3675

As generally length is longer one ,  

So x = 1.0325

From equation (1) y = 15.4 – x = 0.3765

Hence length of the rectangle is 15.0325 km and width is 0.3765 km.

6 0
3 years ago
At the airport, there is a moving walkaway 500 meters long, which moves at a speed of 4 km/hour. Aditya and Ravi step on the wal
Nutka1998 [239]

Answer:

He is approximately 166.6 m ahead of Ravi.

If it's right please mark BRAINLIEST

3 0
2 years ago
Read 2 more answers
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