Using substitution:
first you have to express one variable in terms of the other, in this we can express y in terms of x:

Since both expressions are equal to y, you have to equal both expressions like this:

Now you can solve the equation:

Knowing x=10, you can use any of the expressions we found before to find y. In this case I'm going to use y= -x+9 because it's simpler but boy should give you the same result

So, the answer is x=10 and y=-1
Answer:
x = 20
Step-by-step explanation:
x + 29 = 49
- 29 - 29
x=20
Answer:
1 and -5
Step-by-step explanation:
![~~~~~x^3+3x^2-9x+5=0\\\\\implies x^3-x^2+4x^2-4x-5x+5=0\\\\\implies x^2(x-1)+4x(x-1)-5(x-1)=0\\\\\implies (x-1)(x^2 +4x -5) = 0\\\\\implies (x-1)(x^2+5x -x -5) = 0\\\\\implies (x-1)[x(x+5) -(x+5)] =0\\\\\implies (x-1)(x-1)(x+5)= 0\\\\\implies (x-1)^2(x+5) = 0\\\\\implies x = 1,~~ x = -5](https://tex.z-dn.net/?f=~~~~~x%5E3%2B3x%5E2-9x%2B5%3D0%5C%5C%5C%5C%5Cimplies%20x%5E3-x%5E2%2B4x%5E2-4x-5x%2B5%3D0%5C%5C%5C%5C%5Cimplies%20x%5E2%28x-1%29%2B4x%28x-1%29-5%28x-1%29%3D0%5C%5C%5C%5C%5Cimplies%20%28x-1%29%28x%5E2%20%2B4x%20-5%29%20%3D%200%5C%5C%5C%5C%5Cimplies%20%28x-1%29%28x%5E2%2B5x%20-x%20-5%29%20%3D%200%5C%5C%5C%5C%5Cimplies%20%28x-1%29%5Bx%28x%2B5%29%20-%28x%2B5%29%5D%20%3D0%5C%5C%5C%5C%5Cimplies%20%28x-1%29%28x-1%29%28x%2B5%29%3D%200%5C%5C%5C%5C%5Cimplies%20%28x-1%29%5E2%28x%2B5%29%20%3D%200%5C%5C%5C%5C%5Cimplies%20x%20%3D%201%2C~~%20x%20%3D%20-5)
Answer:
a = 2/3
Step-by-step explanation:
(4(x+1) + 20 )/(x+1) = 16
4x + 4 + 20 = 16x + 16
12x = 8
x = 2/3
I hope this helps you
-3+3. (-4)=16
-3-12=16
-15=16 false