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DiKsa [7]
3 years ago
10

A teacher divides the students into three groups for project each group has the same number of students in the total of number s

tudents prime or composite
Mathematics
1 answer:
alekssr [168]3 years ago
6 0

Answer:

The total number of students is composite

Step-by-step explanation:

* <em>Lets explain how to solve the problem</em>

- A teacher divides the students into three groups for project

- Each group has the same number of students

- We need to know the total number of students is prime number or

 composite number

∵ The least number of any group is 2 students

∵ There are three groups

∵ The number of students in each group equal

∴ The least number of the students is 6

∵ Any number of students must be multiple of 3 because it will

  divide by 3

∵ Any prime number has only two factors 1 and itself

∵ Any multiple of 3 (except 3) has more than two factors

∵ The class can not be 3 students because when divided to 3

   groups each group will have 1 students and the least number of

   students in a group is 2

∴ The number of the students in the class must be composite

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8 0
3 years ago
At a local company, the ages of all new employees hired during the last 10 years are normally distributed. The mean age is 35 ye
Alex73 [517]

Answer:

The probability your mean age will be at least 37 is approximately 26%

Step-by-step explanation:

Let X denote the ages of all new employees hired during the last 10 years , then X is normally distributed with;

a mean of 35

a standard deviation of 10.

The sample size obtained is 10 employees. This implies that the sampling distribution of the sample mean will be normal with;

a mean of 35

a standard deviation of \sqrt{10}

The sample mean is a statistic and thus has its own distribution. Its mean is equal to the population mean, 35 and its standard deviation is equal to \frac{sigma}{\sqrt{n} }

where sigma is the population standard deviation, 10 and n the sample size which in this case is 10. \frac{10}{\sqrt{10} }=\sqrt{10}

We are required to find the probability that this sample mean age will be at least 37;

P(sample mean ≥ 37)

Since we know the distribution of the sample mean we simply standardize it to obtain the z-score associated with it;

P(sample mean ≥ 37)

=P(Z\geq \frac{37-35}{\sqrt{10} })=P(Z\geq0.6325)=1-P(Z

=1 - 0.7365 = 0.2635

=26%

7 0
3 years ago
What is the answer?? Please
Amanda [17]
One must use the division property 
8 0
3 years ago
SOMEBODY HELPPPP MEEE I WOULD PUT YHU AS BRILLIANTEST XJDJJFJRJRNRJTJ
zzz [600]

<em>Add- </em>

0.859+1.63=2.489

<em>Subtract-</em> (Not sure where the decimal was)

0.859-0.03=0.829

0.859-00.3=559

<em>Multiply-</em>

0.859*10^1=8.59

0.859*10^2=85.9

0.859*10^3=859

0.859*10^4=8590

<em>Divide-</em>

0.859/10^1=0.0859

0.859/10^2=0.00859

0.859/10^3=0.000859

0.859/10^4=0.0000859

<em>Round-</em>

0.9

0.86

1

<em>Compare-</em>

<

Hope this helps. Have a nice day. May it be filled with joy and happiness. Please, stay safe and wash your hands. Happy Holidays.

8 0
3 years ago
Round 399,713 to the nearest thousand
solniwko [45]
399,713 rounded to the nearest thousand would be <span>400,000

Hope I Helped!!! :-)

</span>
3 0
3 years ago
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