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mote1985 [20]
4 years ago
10

Which equation has non real solutions

Mathematics
2 answers:
yaroslaw [1]4 years ago
4 0

Answer:

Step-by-step explanation:

hello :

help : ax²+bx+c=0 ....( a≠ 0 )

calculate : Δ = b²-4ac    if Δ<0 you have non real solutions.....continu

Nutka1998 [239]4 years ago
3 0

Answer:

D.

Step-by-step explanation:

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Does this graph show a function explain how you know
In-s [12.5K]
<h3>Answer:</h3>

C. No, the graph fails the vertical line test

<h3>Step-by-step explanation:</h3>

Functions describe the relationship between the dependent variable, y, and the independent variable, x.

Functions

For a graph to be a function, x-values cannot repeat. This means that one x-value cannot have more than one y-value.

However, functions can have repeating y-values. So, y-values can have more than one x-value; as seen in quadratic functions. This means that answer B cannot be correct.

Vertical Line Test

The vertical line test is a way to determine if a graph is a function. A graph passes the vertical line test if you can draw a vertical line at every point on the coordinate plane and not have it intersect with the graph more than once.

On the graph in the question, a vertical line would intersect with the graph twice at the x-values greater than -1. Since the graph fails the vertical line test, it is not a function.

5 0
2 years ago
Left f(x)=x+1 and g(x)=1/x the graph of (f•g) (x) is shown below
Nikolay [14]

Answer:

Range of the function → (-∞, 1)∪(1, ∞)

Step-by-step explanation:

Two function has been given as,

f(x) = (x + 1)

and g(x) = \frac{1}{x}

Then (fog)(x) = f[g(x)]

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As shown in the graph,

Domain of the graph is (-∞, 0) ∪ (0, ∞) [Since vertical asymptote of the function is x = 0, so x = 0 will not be included in the domain]

And the range is (-∞, 1) ∪ (1, ∞) [Since horizontal asymptote is y = 1, so y = 1 will not be included in the range]

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3 years ago
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