F(x)=x^2+2x+1 & g(x)=3(x+1)^2
now, f(x)+g(x)
=x^2+2x+1+3(x+1)^2
=x^2+2x+1+3(x^2+2x+1)
=x^2+2x+1+3x^2+6x+3
=4x^2+8x+4<===answer(c)
next:
f(x)=x^2-1 & g(x)=x+3
now, f(g(x))=(x+3)^ -1
=x^2+6x+9-1
=x^2+6x+8<====answer(b)
i solve two of ur problems.
now try the 3rd one that is similar to no. 1
and try the last two urself.
(4/5) / 8....when ur dividing with fractions, flip what u r dividing by, then multiply
4/5 * 1/8 = 4/40 reduces to 1/10 <=
Answer:
Step-by-step explanation:
6 - 3 = 3
keep the base same, therefore
Hope this helps!
Answer:
165 ways
Step-by-step explanation:
Selection deals with combination
There are a total of 11 from which 3 are to be selected
11C3 = 11!/3!(11-3)!
= 11!/(3!x8!)
=(11x10x9x8!)/(3x2x8!)
=11x10x9/6
=11x5x3 = 165 ways
