He has a total of $45 to buy t tickets, each tickets cost $5

Mathematics

1 answer:

Leona [35]2 years ago

6 0

Answer:

He can buy 9 tickets

You might be interested in

the times in seconds it took 6 finalists to run a 100 meter dash are 12.5 12.4 12.4 12.3 12.6 and 12.4. mr brown picks out the t

yulyashka [42]

Answer:

The times in seconds it took 6 finalists to run a 100 meter dash are 12.5 12.4 12.4 12.3 12.6 and 12.4. Mr. Brown picks out the time that appears the most to find the <u>mode</u> he arranges the times in increasing order and picks the middle value to find the <u>median</u>

3 0

2 years ago

Read 2 more answers

Write an equation of the line that passes through (3,3) and (0,2)

suter [353]

Y=1/3x+2 :))))))))))))))))))))))))

7 0

2 years ago

Read 2 more answers

13. The least common multiple of two non-zero integers a and b is the unique positive integer m such that (i) m is a common mult

Vlad [161]

Answer:

[a,b] divides n

Step-by-step explanation:

Let us denote the least common multiple of a and b [a,b]=m.

We want to prove that m divides n, where n is a multiple of a and b.

We suppose m does not divide n, then by the Division Theorem, there exists q and r integers such that:

(1) ... n=mq+r, where 0<r<m

As n is a multiple of a and b, there exists s and t integers such that:

sa=n and tb=n

Same thing happens to m as it is the least common multiple, there exists u and v such that:

ua=m and vb=m

So (1) has the following form:

n=mq+r ⇒ sa=uaq+r ⇒sa-uaq=r⇒(s-uq)a=r and

n=mq+r ⇒ tb=vbq+r ⇒ tb-vbq=r⇒ (t-vq)b=r

So r is a multiple of a and b, but r<m which is a contradiction as, m is the least common multiple of a and b. So this concludes the proof.

So this means that $\frac{ab}{m}$ is and integer.

As m= vb, then $\frac{m}{b}$ is an integer, lets say $\frac{m}{b}$ =v; and as m=ua, then $\frac{m}{a}$ =u.

So $\frac{ab}{m}$ v= $\frac{ab}{m}$ $\frac{m}{b}$ =a, so $\frac{ab}{m}$ divides a; on the other hand, $\frac{ab}{m}$ u= $\frac{ab}{m}$ $\frac{m}{a}$ =b, so $\frac{ab}{m}$ divides b. From this we can conclude that $\frac{ab}{m}$ is a common divisor of a and b.