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klemol [59]
3 years ago
14

Does anyone know how to solve these types of problems?

Mathematics
2 answers:
LenKa [72]3 years ago
8 0
Sure!
Just simplify the radical by breaking the radicand up into a product of known factors. Like this:
2x^6y^s✔️5
saveliy_v [14]3 years ago
7 0

Answer:

2x^8y^12 sqr root of 5y

Step-by-step explanation:


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If f(x) = 6 – 5x and g(x) = 4x – 1, evaluate f(x) – g(x) for x = –2.
pogonyaev
Hello :
<span>f(x) = 6 – 5x and g(x) = 4x – 1
f(x)-g(x) = 6-5x-(4x-1) = 6-5x-4x+1 = -9x+7
whene x = - 2
f(x)-g(x) = -9(-2)+7 = 25......(answer : D)</span>
6 0
3 years ago
For a school fundraiser, Elena will make pirate masks. She will order masks and print graphics on them. Elena must spend $349 on
SpyIntel [72]

Answer:

135 masks

Step-by-step explanation:

i hope my math is right lol

6 0
2 years ago
Read 2 more answers
How many equivalence relations are there on the set 1, 2, 3]?
Alex787 [66]

Answer:

We need to find how many number of equivalence relations are on the set {1,2,3}

A relation is an equivalence relation if it is reflexive, transitive and symmetric.

equivalence relation R on {1,2,3}

1.For reflexive, it must contain (1,1),(2,2),(3,3)

2.For transitive, it must satisfy: if (x,y)∈R then (y,x)∈R

3. For symmetric, it must satisfy: if (x,y)∈R,(y,z)∈R then (x,z)∈R

Since (1,1),(2,2),(3,3) must be there is R, (1,2),(2,1),(2,3),(3,2),(1,3),(3,1). By symmetry,

we just need to count the number of ways in which we can use the pairs (1,2),(2,3),(1,3) to construct equivalence relations.

This is because if (1,2) is in the relation then (2,1) must be there in the relation.

the relation will be an equivalence relation if we use none of these pairs (1,2),(2,3),(1,3) . There is only one such relation: {(1,1),(2,2),(3,3)}

we can have three possible equivalence relations:

{(1,1),(2,2),(3,3),(1,2),(2,1)}

{(1,1),(2,2),(3,3),(1,3),(3,1)}

{(1,1),(2,2),(3,3),(2,3),(3,2)}

6 0
3 years ago
Lilliana is training for a marathon. She runs the same distance every day for a week. On Monday, Wednesday, and Friday, she runs
Allushta [10]

answer:6

WEDNESDAY + FRIDAY (# OF MILES)

The Miles Covered by Each Lap = 3x

The Miles on Top of That = 6

TUESDAY + SUNDAY (# OF MILES)

The Miles Covered by Each Lap = 5x

The Miles on Top of That = 2

Step-by-step explanation:

6 0
2 years ago
Given that point A is the midpoint of line segment ED, where E( -1,9) and A(4,5), what is the location of point D?
yuradex [85]

Answer:

  D(9, 1)

Step-by-step explanation:

A being the midpoint means its coordinates satisfy ...

  A = (E + D)/2

Solving for D, we find ...

  D = 2A -E

  = 2(4, 5) -(-1, 9) = (2·4 +1, 2·5 -9)

  D = (9, 1)

8 0
3 years ago
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