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soldier1979 [14.2K]
3 years ago
7

X-y=6, x+y=8, zx+zy=20

Mathematics
2 answers:
maxonik [38]3 years ago
7 0

Answer:

X = 7

Y = 1

Z = 2/5

Step-by-step explanation:

7-1 = 6

7+1 = 8

2/5 × 7 + 2/5 = 20

Yanka [14]3 years ago
6 0

Answer:

Step-by-step explanation:

x = 6 + y

6 + y + y = 8

y = 1

x - 1 =6

x = 7

zx + zy = z(x + y) = 20

z = 2.5

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A triangle in Quadrant I is reflected twice, first over the y-axis and then over the x-axis. The new triangle, in Quadrant III,
denpristay [2]

Answer: rotation

Step-by-step explanation:

5 0
3 years ago
Solve using test intervals |x 1|> or equal to 4
insens350 [35]
<span><span>Solve <span>x5 + 3x4 – 23x3 – 51x2 + 94x + 120 </span></span>><span><span> 0</span>. </span></span><span>First, I factor to find the zeroes:<span><span>x5 + 3x4 – 23x3 – 51x2 + 94x + 120</span><span>= (x + 5)(x + 3)(x + 1)(x – 2)(x – 4) = 0</span></span><span>...so </span><span>x = –5, –3, –1, 2,</span><span> and </span>4<span> are the zeroes of this polynomial. (Review how to </span>solve polynomials, if you're not sure how to get this solution.)<span>To solve by the Test-Point Method, I would pick a sample point in each interval, the intervals being </span>(negative infinity, –5)<span>, </span>(–5, –3)<span>, </span>(–3, –1)<span>, </span>(–1, 2)<span>, </span>(2, 4)<span>, and </span>(4, positive infinity). As you can see, if your polynomial or rational function has many factors, the Test-Point Method can become quite time-consuming.<span>To solve by the Factor Method, I would solve each factor for its positivity: </span><span>x + 5 > 0</span><span> for </span><span>x > –5</span>;<span>x + 3 > 0</span><span> for </span><span>x > –3</span><span>; </span><span>x + 1 > 0</span><span> for </span><span>x > –1</span><span>; </span><span>x – 2 > 0</span><span> for </span><span>x > 2</span><span>; and </span><span>x – 4 > 0</span><span> for </span><span>x > 4</span>. Then I draw the grid:...and fill it in:...and solve:<span>Then the solution (remembering to include the endpoints, because this is an "or equal to" inequality) is the set of </span>x-values in the intervals<span> [–5, –3]<span>, </span>[–1, 2]<span>, and </span>[4, positive infinity]</span>. </span>

As you can see, if your polynomial or rational function has many factors, the Factor Method can be much faster.

<span>
</span>
4 0
3 years ago
What are the coefficients of the expression -sup(x,2)+9x?
skad [1K]

The coefficients in the expression are -1 and 9

<h3>How to determine the coefficients?</h3>

The expression is given as:

-x^2 + 9x

In an expression ax, the coefficient is a.

Using the above as a guide, we have:

-x^2 + 9x

The coefficients in the above expression are -1 and 9

Read more about coefficients at:

brainly.com/question/27481600

#SPJ1

7 0
2 years ago
I need help pls <br><br> I WILL GIVE BRAINLIEST <br> Pls help
uranmaximum [27]

Answer:

1. The square root of 100

2.c=27.11

d=13.96

e=12.6

<u>Step</u><u> </u><u>by</u><u> </u><u>step</u><u> </u><u>explanation</u><u>:</u><u> </u>

1. 2×50=100 the geometric mean is the square root of 100

2. The diagram is made up of three right angled triangles the big outer one and two triangles inside the big one thus we can use the pythagorean theorem to come up with expressions which will help us in solving the unknown parts as below.

c²=30²-d²

c²=e²+24²

d²=e²+6²

both the following add up to c² meaning they are equal:

c²=30²-d²

c²=e²+24²

thus

30²-d²=e²+24²

I want to remain with d² only thus;

30²-24²-e²=d²

900-576=324 (squareroot of 324=18) so

d²=18²-e² and d²=e²+6²

both the above add up to d² meaning they are equal thus;

18²-e²=e²+6²

18²-6²=e²+e²

324-36=2e²

318=2e²

159=e²

e=12.61

<em>Thus</em><em> </em><em>d</em><em>²</em><em>=</em><em>e</em><em>²</em><em>+</em><em>6</em><em>²</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>d</em><em>²</em><em>=</em><em>1</em><em>2</em><em>.</em><em>6</em><em>1</em><em>²</em><em>+</em><em>6</em><em>²</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>d</em><em>²</em><em>=</em><em>1</em><em>5</em><em>9</em><em>+</em><em>3</em><em>6</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>d</em><em>²</em><em>=</em><em>1</em><em>9</em><em>5</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>d</em><em>=</em><em>1</em><em>3</em><em>.</em><em>9</em><em>6</em>

<em>c</em><em>²</em><em>=</em><em>e</em><em>²</em><em>+</em><em>2</em><em>4</em><em>²</em>

<em>c</em><em>²</em><em>=</em><em>12.61</em><em>²</em><em>+</em><em>2</em><em>4</em><em>²</em>

<em>c</em><em>²</em><em>=</em><em>1</em><em>5</em><em>9</em><em>+</em><em>5</em><em>7</em><em>6</em>

<em>c</em><em>²</em><em>=</em><em>7</em><em>3</em><em>5</em>

<em>c</em><em>=</em><em>27.11</em>

<em> </em>

<em>I</em><em> </em><em>hope</em><em> </em><em>this</em><em> </em><em>helps</em>

3 0
3 years ago
Factor this expression. You will need to show your work for full credit. b^2-6b+8
Ostrovityanka [42]
B^2-6b+8 turns into b^2-2b-4b+8 due to the sum product pattern. which then turns into b(b-2) - 4(b-2) and then its (b-4)(b-2)
4 0
3 years ago
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